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4 years ago

Hanging from a horizontal beam are nine simple pendulums of the following lengths:

Physics

1 answer:

LenaWriter [7]4 years ago

8 0

Answer:

Options d and e

Explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

$L =\frac{g}{w^{2} }$

where g=9.8m/s

ω= 2rad/s to 4rad/sec

when ω= 2rad/sec

$L= \frac{9.8}{2^{2} }$

L = 2.45m

when ω= 4rad/sec

$L=\frac{9.8}{4^{2} }$

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

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A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,

muminat

Answer:

The speed of the plank relative to the ice is:

$v_{p}=-0.33\: m/s$

Explanation:

Here we can use momentum conservation. Do not forget it is relative to the ice.

$m_{g}v_{g}+m_{p}v_{p}=0$ (1)

Where:

m(g) is the mass of the girl
m(p) is the mass of the plank
v(g) is the speed of the girl
v(p) is the speed of the plank

Now, as we have relative velocities, we have:

$v_{g/b}=v_{g}-v_{p}=1.55 \: m/s$ (2)

v(g/b) is the speed of the girl relative to the plank

Solving the system of equations (1) and (2)

$45v_{g}+168v_{p}=0$

$v_{g}-v_{p}=1.55$

$v_{p}=-0.33\: m/s$

I hope it helps you!

8 0

3 years ago

A student dips a strip of metal into a liquid. Which is evidence that only a physical change has occurred?

sattari [20]

Answer:

PLS add the picture too.....

3 0

3 years ago

Please, I need help with this.

solmaris [256]

this is the answer :)

6 0

3 years ago

Read 2 more answers

Perpendicular parking spaces require turning at a ______-degree angle.

Archy [21]

Perpendicular means at 90 degree angle. so,
<span>Perpendicular parking spaces require turning at a 90 degree angle.

When you are going to park perpendicularly, you need a distance of 7 to 8 feet from the vehicle you are parking next to, and when you are parking parallel, you need 5 feet distance from the vehicle you are parking next to.</span>

7 0

3 years ago

Ammonia at 10◦c with a mass of 10 kg is in a piston/cylinder assembly with an initial volume of 1 m3. the piston initially resti

jeyben [28]

Here mass is floating on the piston at equilibrium

So it will have constant pressure always remains constant

So final pressure is same as initial pressure = 900 kPa

now we can say

$\frac{V_1}{V_2} = \frac{T_1}{T_2}$