Question

Factor completely. 6y^2-5y+1

Answer 1

Factor 6y2−5y+16y2−5y+1=(3y−1)(2y−1)Answer:(3y−1)(2y−1)

Answer 2

Step-1 : Multiply the coefficient of the first term by the constant   6 • -1 = -6 

Step-2 : Find two factors of  -6  whose sum equals the coefficient of the middle term, which is   -5 .

     -6   +   1   =   -5   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -6  and  1 
                     6y2 - 6y + 1y - 1

Step-4 : Add up the first 2 terms, pulling out like factors :
                    6y • (y-1)
              Add up the last 2 terms, pulling out common factors :
                     1 • (y-1)
Step-5 : Add up the four terms of step 4 :
                    (6y+1)  •  (y-1)
             Which is the desired factorization

Final result : (y - 1) • (6y + 1)