Ask question

Ask question

All categories

3 years ago

7

Factor completely. 6y^2-5y+1

2 answers:

Bess [88]3 years ago

8 0

Factor <span><span><span>6<span>y2</span></span>−<span>5y</span></span>+1</span><span><span><span>6<span>y2</span></span>−<span>5y</span></span>+1</span><span>=<span><span>(<span><span>3y</span>−1</span>)</span><span>(<span><span>2y</span>−1</span>)</span></span></span>Answer:<span><span>(<span><span>3y</span>−1</span>)</span><span>(<span><span>2y</span>−1</span><span>)</span></span></span>

Deffense [45]3 years ago

6 0

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -1 = -6</span>

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is <span> -5 </span>.

<span> -6 + 1 = -5 That's it</span>

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -6  and  1
                     <span>6y2 - 6y</span> + 1y - 1

Step-4 : Add up the first 2 terms, pulling out like factors :
                    6y • (y-1)
              Add up the last 2 terms, pulling out common factors :
                     1 • (y-1)
Step-5 : Add up the four terms of step 4 :
                    (6y+1)  •  (y-1)
             Which is the desired factorization

Final result :<span> (y - 1) • (6y + 1)</span>

You might be interested in

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

PLZ HELP ME BY THE END OF THE DAY

nlexa [21]

$3x^{2} +1=28$

Step 1 : subtract 1 from both sides

$3x^{2} =27$

Step 2 : Divide both sides by 3

$\frac{\frac{3x^{2} }{3} }{\frac{27}{3} }$

$x^{2} = 9$

Step 3 : Find the square root of 9

$\sqrt{9} = 3$

x= (-3,3)

remember negative × negative = positive

6 0

3 years ago

What is the factores form of (2x^2+11x-40)?

Cerrena [4.2K]

${2x}^{2} + 11x - 40 \\ = (2x - 5)(x + 8)$

Hope this helps. - M

7 0

3 years ago

Which term describes the point where the perpendicular bisectors of the three sides of a triangle intersect

MissTica

Given statement is "point where the perpendicular bisectors of the three sides of a triangle intersect".

Perpendicular is basically a vertical line that makes 90 degree angle with the base.

bisector means the line which divides side into two equal parts.

So perpendicular bisector in any triangle will be the line which is drawn on the side of the triangle and perpendicular to that side.

Now these perpendicular bisectors meet at some point.

That point is called circumcenter.

Hence final answer will be "circumcenter".

6 0

3 years ago

Read 2 more answers

Does 3/20 have a repeating decimal form

olga_2 [115]

nope, this answer is 0.15

6 0

2 years ago