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solniwko [45]
4 years ago
7

Factor completely. 6y^2-5y+1

Mathematics
2 answers:
Bess [88]4 years ago
8 0
Factor <span><span><span>6<span>y2</span></span>−<span>5y</span></span>+1</span><span><span><span>6<span>y2</span></span>−<span>5y</span></span>+1</span><span>=<span><span>(<span><span>3y</span>−1</span>)</span><span>(<span><span>2y</span>−1</span>)</span></span></span>Answer:<span><span>(<span><span>3y</span>−1</span>)</span><span>(<span><span>2y</span>−1</span><span>)</span></span></span>
Deffense [45]4 years ago
6 0

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -1 = -6</span> 

Step-2 : Find two factors of  -6  whose sum equals the coefficient of the middle term, which is  <span> -5 </span>.

<span>     -6   +   1   =   -5   That's it</span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -6  and  1 
                     <span>6y2 - 6y</span> + 1y - 1

Step-4 : Add up the first 2 terms, pulling out like factors :
                    6y • (y-1)
              Add up the last 2 terms, pulling out common factors :
                     1 • (y-1)
Step-5 : Add up the four terms of step 4 :
                    (6y+1)  •  (y-1)
             Which is the desired factorization

Final result :<span> (y - 1) • (6y + 1)</span>
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