Just substitute the values: -1/-10-6 -> -1/-16 -> 1/16.
We know that the polynomial function is of degree 3, and that its roots are -4, 0, 2.
With this data we can write a generic equation for the function:
f (x) = bx (x + 4) (x-2)
Since the function is of degree 3 and cuts the axis at x = 0, then it has rotational symmetry with respect to the origin.
The graph of the function can be of two main forms, based on the value of the coefficient b.
If b is positive then the function grows from y = -infinite and cuts the x-axis for the first time in -4. Then it decreases, cuts at x = 0 and begins to grow again cutting the x-axis for the third time at x = 2. and continues to grow until y = infnit
If b is negative, then the function decreases from y = infinity and cuts the x-axis for the first time in -4. Then it grows, cuts at x = 0 and begins to decrease again by cutting the x-axis for the third time at x = 2, and continues to decrease until y = -infnit.
In the attached images the graphs of the function f (x) are shown assuming b = -1 and b = 1
Answer:
Step-by-step explanation:
<u>The function in vertex form:</u>
<u>x- intercepts are 15 and 35:</u>
- 0 = a(15 - 25)² + 32 or 0 = a(35 - 25)² + 32
- 0 = a*100 + 32
- 100a = - 32
- a = -32/100
- a = -8/25 or -0.32
Answer:
ft if
Step-by-step explanation:
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Answer:
B. n || m
Step-by-step explanation:
Lines m and n are intersected by tranversal k. Alternate exterior angles 1 and 2 are congruent. Therefore, lines m and n are parallel. That is the only conclusion you can draw.
Answer: B. n || m