What is the range of the data set? {43.2, 46.8, 44.5, 46.8, 44.2, 41.9, 45.8, 46.9, 41.2, 46.8, 44.1}

Mathematics

1 answer:

lilavasa [31]3 years ago

3 0

Answer:

the range of this answer is 5.6

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joja [24]

<span>you would take 3/4 and multiply it by six or to make it easyier just take the three and add it six times which is 18 thn you take 18 and divide it by 4 which you cant evenly so take 18/4 and reduce it which is 4 cup and 2/4 or 1/2</span>

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How much money does the average professional hockey fan spend on food at a single hockey game? That question was posed to 10 ra

Vinil7 [7]

Answer:

Now we have everything in order to replace into formula (1):

$18-2.262\frac{2.75}{\sqrt{10}}=16.03$

$18+2.262\frac{2.75}{\sqrt{10}}=19.97$

Step-by-step explanation:

Information given

$\bar X=18$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.75 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=10-1=9$

The Confidence is 0.90 or 90%, the significance is $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical vaue would be $t_{\alpha/2}=2.262$

Now we have everything in order to replace into formula (1):

$18-2.262\frac{2.75}{\sqrt{10}}=16.03$

$18+2.262\frac{2.75}{\sqrt{10}}=19.97$

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2 years ago

Find the equation of the line containing the points (20,-7) and (10,-2). Type your answer in this order and don't use spaces or

aliina [53]

$(\stackrel{x_1}{20}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{20}}}\implies \cfrac{-2+7}{-10}\implies -\cfrac{1}{2}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{1}{2}}(x-\stackrel{x_1}{20}) \\\\\\ y+7=-\cfrac{1}{2}x+10\implies y=-\cfrac{1}{2}x+3$