Answer:

Step-by-step explanation:
<u>System of Equations</u>
Let's call:
x = number of nickels in the student's pocket
y = number of dimes in the student's pocket
Each nickel has a value of $0.05, so x nickels have a value of 0.05x
Each dime has a value of $0.10, so y dimes have a value of 0.10y
The student has a total of 10 coins, thus:

The total value of the coins is $0.85, thus

The system of linear equations that represents this scenario is:

Move all terms that don't contain y to the right side and solve.
y = - x/3 + 14/3
Hope this helps! :)
Answer:
(19 , -14)
Step-by-step explanation:
Find the distance in between each x & y for a coordinate.
Let: (x₁ , y₁) = (-1 , 2)
Let: (x₂ , y₂) = (9 , -6)
From x₁ ⇒ x₂: 9 - (-1) = 10
From y₁ ⇒ y₂: -6 - 2 = -8 = 8*
*Remember that distance cannot be negative, but for the sake of this question, we will leave it as -8.
The distance between the x points are in intervals of 10. The distance between the y points are in intervals of 8. Add 10 & subtract 8 to their respective numbers to get endpoint 2:
(9 (+ 10) , -6 (- 8)) = (19 , -14)
Endpoint 2 = (19 , -14)
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brainly won't let me type my answer out so i'll just put it in the comments, sorry if it's inconvenient.
Answer:
Step-by-step explanation:
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.
a) Let X represent the price of the option
<h3><u> x P(X=x)
</u></h3>
$1000 20/100 = 0.2
$200 50/100 = 0.5
$0 30/100 = 0.3
b) Expected option price

Therefore expected gain = $300 - $150 = $150
c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.