Answer:
for binary 101111010001. for octal 5721. for base 5 - 44100
A class has LESS THAN 30 students
we must find what number is less than 30 and divides into both 4 and 8 so that we don't have a fraction of a student owning a football boot
the class could have 8 students
the class could have 16 students
the class could have 24 students
<u>lets assume that the class has the max possible so </u>
<u>24 in the class</u>
so we must find a coommon denomenator (bottom number) to keep the fractions the same we must multiply it by 1 or (number)/(same number as on top) or 1/1
so 3/4 times 2/2=6/8
7/8
so we must assume that the ones who own footballs also have boots (and not some other random person) so
6/8 or 3/4 of the class owns both football boots so
3/4 times 24=18
18 students own football boots
Answer: The solution is,
Step-by-step explanation:
Given equations are,
,
From the above equations,
First approximation,
Second approximation,
Third approximation,
Fourth approximation,
Fifth approximation,
Hence, by the Gauss Seidel method the solution of the given system is,
32.4*0.69=22.149
...
45=3*3*5, 63=3*3*7 The greatest common factor is the product of shared primes of the numbers prime factorization. In this case 3*3=9 is the product of shared primes so the greatest common factor is 9
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