Answer:
SAS Postulate
Step-by-step explanation:
You can use the SAS (side, angle, side) postulate that says "if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent"
Side AB is proportionate to DE and
Side AC is proportionate to DF.
Angle A and Angle D are the same; and is between the two sides
I hope this helps.
Answer:
Graph the triangle at points (1,5), (1,8), and (6,8)
Step-by-step explanation:
Since the rule is (x,y) -> (y,x), that just means swapping the value of x and y.
The first point (5,1) has 5 for x and 1 for y. If you swap the values, you get 1 for x and 5 for y, or (1,5).
The second point is (8,6). If you swap x and y you get (6,8). Notice I'm not doing the inverse of each number by making them negative, just swapping the twp values.
The third point is (8,1) and if you swap x and y you should get (1,8).
The transformation rule applies to ALL points, otherwise it wouldn't look right and it wouldnt be transforming.
I hope this helps :)
The slope is 5/3 since it rises 5 then runs 3 and is positive.
Answer:
Step-by-step explanation:
Hello!
Maria and John want to adopt a pet. The animals available for adoption are:
7 Siamese cats
9 common cats
4 German Shepherds
2 Labrador Retrievers
6 mixed-breed dogs
Total pets available: 28
To reach the probability of each pet category you have to divide the number of observed pets for the said category by the total of pets available for adoption:
P(Siam)= 7/28= 0.25
P(Comm)= 9/28= 0.32
P(Ger)= 4/28= 0.14
P(Lab)= 2/28=0.07
P(Mix)= 6/28=0.21
a.
You need to calculate the probability that the selected pet is a cat, this situation includes the categories "Siamese" and "common cat"
P(Cat)= P(Siam) + P(Comm)= 0.25+0.32= 0.57
b.
You have a total of 16 cats out of 28 pets. If you express it in the ratio: 16:28 → using 4 as a common denominator the odds of selecting a cat is: 4:7
c.
P(Cat∪Mix)
The events "cat" and "mixed-breed dog" are mutually exclusive, so you can calculate the probability of the union of both events as:
P(Cat∪Mix)= P(Cat)+P(Mix)= 0.57+0.21= 0.78
d.
Now you are in the situation that they select a dog that is not a labrador, this situation includes the categories " German shepherd" and "mixed-breed"
P(NotLab)= P(Ger)+P(Mix)= 0.14 + 0.21= 0.35
I hope this helps!
