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3 years ago

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A trapezoid has an area of 329 square feet. If the bases are 30 feet and 17 feet, what is the height of the trapezoid in feet? F

ormula: h = 2A / b1 +b2?
A.13.5sq ft
B.14.5sq ft
C.14sq ft
PLS ANSWER ASAP

1 answer:

ExtremeBDS [4]3 years ago

6 0

Answer:

The correct option is C. 14 ft

Step-by-step explanation:

To calculate the height, we will follow the steps below;

Formula is given to be: h = 2A / b1 +b2

where h = height of the trapezoid b1 and b2 are the bases of the trapezoid and A is the area of the trapezoid

From the question given;

Area A =329 feet² b1 = 30 feet b2 =17 feet

We can now proceed to insert the values into the formula

h = 2A / b1 +b2

h= 2(329) / 30 + 17

h = 658 /47

h=14 feet

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1. Find the digit that makes 3,71_ divisible by 9.

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<u>QUESTION 1</u>

We want to find the digit that should fill the blank space to make

$3,71-$

divisible by 9.

If a number is divisible by 9 then the sum of the digits should be a multiple of 9.

The sum of the given digits is,

$3 + 7 + 1 = 11$

Since

$11 + 7 = 18$

which is a multiple of 9.

This means that

$3,717$

is divisible by 9.

The correct answer is B

<u>QUESTION 2</u>

The factors of the number 30 are all the numbers that divides 30 exactly without a remainder.

These numbers are ;

$1,2,3,5,6,10,15,30$

The correct answer is A.

<u>QUESTION 3.</u>

We want to find the prime factorization of the number 168.

The prime numbers that are factors of 168 are

$2,3 \: and \: 7$

We can write 168 as the product of these three prime numbers to obtain,

$168={2}^{3}\times 3\times7$

We can also use the factor tree as shown in the attachment to write the prime factorization of 168 as

$168 ={2}^{3}\times 3\times7$

The correct answer is B.

QUESTION 4.

We want to find the greatest common factor of

$140\:\:and\:\:180$

We need to express each of these numbers as a product of prime factors.

The prime factorization of 140 is

$140={2}^{2}\times 5\times7.$

The prime factorization of 180 is

$180={2}^{2} \times{3}^{2}\times5.$

The greatest common factor is the product of the least degree of each common factor.

$GCF={2}^{2}\times5$

$GCF=20$

The correct answer is A.

QUESTION 5.

We want to find the greatest common factor of

$15,30\: and\:60.$

We need to first find the prime factorization of each number.

The prime factorization of 15 is

$15=3\times5.$

The prime factorization of 30 is

$30=2\times 3\times 5.$

The prime factorization of 60 is

$60={2}^{2}\times3 \times5$

The greatest common factor of these three numbers is the product of the factors with the least degree that is common to them.

$GCF=3 \times5$

$GCF=15$

The correct answer is C.

QUESTION 6

We want to determine which of the given fractions is equivalent to

$\frac{3}{8}.$

We must therefore simplify each option,

$A.\: \: \frac{15}{32}=\frac{15}{32}$

$B.\:\:\frac{12}{32}=\frac{4\times 3}{4\times8}=\frac{3}{8}$

$C.\:\:\:\:\frac{12}{24}=\frac{12\times1}{12\times 2}=\frac{1}{2}$

$D.\:\:\frac{9}{32}=\frac{9}{32}$

The simplification shows that

$\frac{12}{32}\equiv \frac{3}{8}$

The correct answer is B.

QUESTION 7.

We want to express

$\frac{10}{22}$

in the simplest form.

We just have to cancel out common factors as follows.

$\frac{10}{22}=\frac{2\times5}{2 \times11}$

This simplifies to,

$\frac{10}{22}=\frac{5}{11}$

The correct answer is C.

QUESTION 8.

We were given that Justin visited $25$ of the $50$ states.

The question requires that we express $25$ as a fraction of $50.$

This will give us

$\frac{25}{50}=\frac{25\times1}{25\times2}$

We must cancel out the common factors to have our fraction in the simplest form.

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The correct answer is C.

QUESTION 9.

We want to write

$2\frac{5}{8}$

as an improper fraction.

We need to multiply the 2 by the denominator which is 8 and add the product to 5 and then express the result over 8.

This gives us,

$2 \frac{5}{8}=\frac{2\times8+5}{8}$

this implies that,

$2\frac{5}{8}=\frac{16+5}{8}$

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QUESTION 10

See attachment

QUESTION 11

We wan to write

$3\: and\:\:\frac{7}{8}$

as an improper fraction.

This implies that,

$3+\frac{7}{8}=3\frac{7}{8}$

To write this as a mixed number, we have,

$3\frac{7}{8}=\frac{3\times8+7}{8}$

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QUESTION 12

We want to find the LCM of $30$ and $46$ using prime factorization.

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The prime factorization of 46 is $40=2\times 23$ .

The LCM is the product of the common factors with the highest degrees. This gives us,

$LCM=2\times \times3 5\times 23$

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The correct answer is D.

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We want to find the least common multiple of 3,6 and 7.

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The prime factorization of 7 is $7$ .

The LCM is the product of the common factors with the highest degrees. This gives us,

$LCM=2\times3 \times7$

$LCM=42$ .

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The correct answer is B.

See attachment for continuation.

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Read 2 more answers

Somebody please explain this I have a major exam soon and I really need to know how to solve problems like this

nevsk [136]

Answer:

y = 2x - 3

Step-by-step explanation:

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y2= 5

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x2 = 4

x1 = 2

Plug in the numbers into the equation. 5 - 1 is 4. 4 - 2 is 2. 4/2 is 2. There. Our slope is 2.

Step 2: Find the b value. Keep in mind that an equation in point-slope form is y = mx + b, where m = the slope, and b = the y-intercept. For this part, you will plug in one of the points as x and y to find the b value. let's use point (4, 5)

The equation then becomes 5 = 2(4) + b. As we know, 2 * 4 is 8. Subtract 8 on both sides of the equation to cancel out the right side and isolate the b variable. 5 - 8 is -3. Even if you use the other point for the equation (1 = 2(2) +b), you should get the same answer of -3.

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