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lapo4ka [179]
3 years ago
6

Suppose you have two 100-mL graduated cylinders. In each cylinder there is 40.0mL of water. You also have two cubes: one is lead

, and the other is aluminum. Each cube measures 3.0cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders?
Chemistry
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

67 mL

Explanation:

In each cylinder there is 40.0 mL of water.

volume of each cube = L × L × L = 3 cm × 3 cm × 3 cm = 27 cm³

when a substance is suspended in a liquid, the substance will displaced liquid equal to its own volume.

1 cm³ = 1 ml

27 cm³ = 27 mL

the new water level equal = 40.0 mL + 27 mL = 67 mL in each cylinders

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A 6.000L tank at 19.2°C is filled with 18.0g of carbon monoxide gas and 10.6g of chlorine pentafluoride gas. You can assume both
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Answer:

Total pressure: 2.89 atm

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We should apply the Ideal Gases Law to solve this:

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We need n, which is the total moles for the mixture

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So we have the total moles so with the formula we would know the total pressure.

P . 6L = 0.724 mol . 0.082L.atm/mol.K . 292.2K

P = ( 0.724 mol . 0.082L.atm/mol.K . 292.2K) / 6L

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Mole fraction is defined as the quotient between the moles of gas over total moles, and it is equal to partial pressure of that gas over total pressure

Moles of gas X /Total moles = Partial pressure of gas X/Total pressure

(Moles of gas X / Total moles) . Total pressure = Partial pressure of gas X

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Partial pressure CO = 0.88 . 2.89 atm → 2.56 atm

Mole fraction ClF₅ = 0.0812 / 0.724 = 0.12

Partial pressure ClF₅ = 0.12 . 2.89 atm → 0.33 atm

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