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igor_vitrenko [27]
2 years ago
9

What is ozone ? A) dissolved oxygen B) the main catalyst in photosynthesis C) a type of oxygen D) a form of calcium carbonate

Chemistry
2 answers:
kykrilka [37]2 years ago
7 0

Answer:

C)

Explanation:

ozone is a type of oxygen. It's chemical compound is 03. Just 1 more molecule than regualr oxygen.

Glad I was able to help!!

Marrrta [24]2 years ago
5 0

Answer:

C a type of oxygen

Explanation:

Ozone is a substance whose molecule is composed of three oxygen atoms, formed by dissociating the two atoms that make up the oxygen gas.

molecular structure of oxygen: O_2

Molecular structure of ozone:  O_3

Ozone is an allotrope of oxygen this means that they are molecules formed by the same element (a single element) and that it has a different molecular structure

Therefore the correct option is C a type of oxygen

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Lunna [17]

Answer:

20 cats.

Explanation:

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3 years ago
What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.
Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

Hence, the hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

3 0
3 years ago
Calculate how many moles of Ca(OH)2 are needed to produce 4.8 x 1024 NH3 molecules, according to the following equation
bonufazy [111]

Answer:

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3 years ago
The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

K_{sp}=(3S)^3\times (2S)^2

K_{sp}=108S^5

K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}

pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90

5 0
2 years ago
Need help with this ASAP<br><br> Thanks!
olga_2 [115]

Answer:

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Explanation:

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