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Art [367]
2 years ago
11

I need help filling out this table, please help ASAP

Chemistry
2 answers:
aleksandr82 [10.1K]2 years ago
6 0

Answer:

A-20 B-40 C-Ca D-10 E-9 F-F

Dovator [93]2 years ago
3 0

Explanation:

<h2>----------------------------------------------</h2><h2>atomic number= no.of protons</h2><h2>and </h2>

<h2>mass no.= no. of protons+no. of neutrons</h2><h2>__________________________</h2><h2><em>A</em><em>=</em><em> </em><em>2</em><em>0</em></h2><h2><em>B</em><em>=</em><em> </em><em>4</em><em>0</em></h2><h2><em>C=</em><em> </em><em>ca</em></h2><h2><em>D</em><em>=</em><em> </em><em>1</em><em>0</em></h2><h2><em>E</em><em>=</em><em> </em><em>9</em></h2><h2><em>F</em><em>=</em><em>F</em></h2>

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3 years ago
If we start with 8000 atoms of radium-226 how much would remain after 3200 years?
olya-2409 [2.1K]
<h3>Answer:</h3>

2000 atoms

<h3>Explanation:</h3>

We are given the following;

Initial number of atoms of radium-226 as 8000 atoms

Time taken for the decay 3200 years

We are required to determine the number of atoms that will remain after 3200 years.

We need to know the half life of Radium

  • Half life is the time taken by a radio active material to decay by half of its initial amount.
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Remaining amount = Original amount × 0.5^n

where n is the number of half lives

n = 3200 years ÷ 1600 years

 = 2

Therefore;

Remaining amount = 8000 atoms × 0.5^2

                                = 8000 × 0.25

                                 = 2000 atoms

Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.

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