M=7M(H₂O)
M=7*18.015 g/mol = 126.105 g/mol
<h3>
Answer:</h3>
2000 atoms
<h3>
Explanation:</h3>
We are given the following;
Initial number of atoms of radium-226 as 8000 atoms
Time taken for the decay 3200 years
We are required to determine the number of atoms that will remain after 3200 years.
We need to know the half life of Radium
- Half life is the time taken by a radio active material to decay by half of its initial amount.
- Half life of Radium-226 is 1600 years
- Therefore, using the formula;
Remaining amount = Original amount × 0.5^n
where n is the number of half lives
n = 3200 years ÷ 1600 years
= 2
Therefore;
Remaining amount = 8000 atoms × 0.5^2
= 8000 × 0.25
= 2000 atoms
Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.
Hydrogen .<span>carbon dioxide is CO2 and </span><span>glucose is C6H12O6</span>
The giant piles of mining waste called tailings. These wastes consists of ground rock and process effluents from a mining plant. These wastes are stored on a surface either in a facility or in the form of piles. Also, sometimes it is stored underground in areas that are mined out.
