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Bas_tet [7]
3 years ago
10

Write the equation of a circle whose center is at the origin and contains the point (7,0)

Mathematics
1 answer:
Sonja [21]3 years ago
4 0

{x}^{2}  +  {y}^{2}  - 14 = 0

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Can you explain it and help me out please​
shusha [124]

Answer:

D. two real solutions

Step-by-step explanation:

p²+5 = 6p

p² - 6p +5 =0

D = b² - 4ac = (-6)² - 4*(1)*5 = 36 - 20 = 16

D > 0, so this equation has 2 real solutions

4 0
3 years ago
Which of the following expressions are equivalent to the expression below?
sergejj [24]

Answer:

8(x+4y)

8x+32y

Step-by-step explanation:

please mark me as brainlest

7 0
2 years ago
Please someone help! You have to make this word problem into an inequality.
labwork [276]

Answer:

the theater needs to sell at least 100 tickets

Step-by-step explanation:

wants to make at least $1000 and they already have $50, so you take the $9.50 per ticket and add that to the $50.

$1000=$9.50t+$50

1000/50=9.5t

950=9.5t

950/9.5=t

t=100

4 0
3 years ago
Which expression is equivalent to 2 (t-4) +1. A 2t-5 B.2t-7 C. 2t-9 D. 2t -3
seraphim [82]

Answer: 2t + -8

Step-by-step explanation: Let's simplify this problem using the distributive property.

The first thing we want to do is change this minus to plus a negative.

Now we can distribute or multiply this 2 times

each of the terms inside the set of parentheses.

So we get 2(t) + 2(-4) and this simplifies to 2t + -8.

2t + -8 is the same thing as 2t -8.

8 0
3 years ago
How many digits are written when 1000 to the power of 2015 is expressed as a numeral?
PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

1000^{2015}

We have to find the number of digits ,

So,

1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}

Since we know that

10^n\text{ has n+1 number of digits }

so,

10^{6045}\text{ has 6046 number of digits }

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0
3 years ago
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