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Reil [10]
3 years ago
5

A car traveling initially at +7.0 m/s accelerates uniformly at the rate of +0.80 m/s² for a distance of 245 m.

Physics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

(a) 21 m/s

(b) 15.78 m/s

(c) 12.5 m/s

Explanation:

Given;

Initial velocity, u = +7.0 m/s

accelerates, a = +0.80 m/s²

distance, s = 245 m

One of equation of motions is given by;

                                v^{2} = u^{2} + 2as

where,

v is the final velocity in m/s

u is the initial velocity in m/s

a is the acceleration in m/s²

s is the distance in m

(a) The velocity of the car at end of the acceleration will be when it covers 245 m

                              v^{2} = 7^{2} + (2 \ * 0.80s \ *  245)

                              v^{2} = 49 + 392

                              v^{2} = 441

                              v = \sqrt{441}

                              v = 21 \ m/s

(b)  Velocity after the car accelerates for 125 m            

                            v^{2} = 7^{2} + (2 \ * 0.80s \ *  125)

                             v^{2} = 49 + 200

                             v^{2} = 249

                             v = \sqrt{249}

                             v = 15.78 \ m/s

(c)  Velocity after the car accelerates for 67 m                      

                             v^{2} = 7^{2} + (2 \ * 0.80s \ *  67)

                             v^{2} = 49 + 107.2

                             v^{2} = 156.2

                             v = \sqrt{156.2}

                             v = 12.5 \ m/s

 

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