Question

A firefighter slides down a pole in a fire station with an acceleration of 7.8 m/s2 . If the firefighter starts at rest and slides for a distance of 3.7 m , what is his final speed?

Answer 1

Answer:

The final speed of a firefighter is 7.59 m/s.        

Explanation:

Given that,

Acceleration of a firefighter, $a=7.8\ m/s^2$

Initial speed of firefighter, u = 0 (at rest)

Distance covered, d = 3.7 m

Let v is his final speed. using third equation of motion to find it as :

$v^2-u^2=2ad\\\\v^2=2ad\\\\v=\sqrt{2\times 7.8\times 3.7} \\\\v=7.59\ m/s$

So, the final speed of a firefighter is 7.59 m/s.