From our studies of the work of Professor Newton,
we have learned that
F = M a .
That is, the product of an object's mass and its acceleration
is equal to the net force acting on it.
An object in equilibrium is an object that has no acceleration.
In other words, it may be moving in a straight line at a speed
that does not change, or it may be just lying there before us.
In either case, since the object has no acceleration, we glance
at Newton's formula, and we instantly realize that the net force
on the object must be ZERO.
The object behaves just as if there were NO forces acting on it at all.
Answer:
29.2 ft/s
Explanation:
The distance of the light's projection on the wall
y = 13 tan θ
where θ is the light's angle from perpendicular to the wall.
The light completes one rotation every 3 seconds, that is, 2π in 3 seconds,
Angular speed = w = (2π/3)
w = (θ/t)
θ = wt = (2πt/3)
(dθ/dt) = (2π/3)
y = 13 tan θ
(dy/dt) = 13 sec² θ (dθ/dt)
(dy/dt) = 13 sec² θ (2π/3)
(dy/dt) = (26π/3) sec² θ
when θ = 15°
(dy/dt) = (26π/3) sec² (15°)
(dy/dt) = 29.2 ft/s
F = ma
Rearrange this so acceleration is the subject:
A = f/m
Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s
Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s
For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)
1897 Because he was doing an experiment at that time .
