The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.
To find the electrical force, distance = 2 meters
charge q1 = 2×10⁻⁶ C
charge q2 = 4×10⁻⁶ C
<h3>Define coulomb's law and solve with formula.</h3>
The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.
Formula can be written as,
F = K ( q1q2 / r² )
F - electric force
k - Coulomb constant
q1, q2 - charges
r - distance of separation
Substituting the values in the formula,
F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C × 4×10⁻⁶ C) / (2²))
= 0.0179751
F = 1.8 × 10 ⁻² N.
As both the charges q1 and q2 are positive, the charges gets repulsive.
SO, the correct answer is Option A.
Learn more about coulomb's law,
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