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2 years ago

9

I need help with this problem asap

1 answer:

Montano1993 [528]2 years ago

3 0

A . 104 x 5.

Hope this helps

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Please answer thanks a lot!

Evgen [1.6K]

Vol (pyr) = 1/3 b × h, where h = 15 and b = base = area of triangular base = 1/2 b×h, where h = 12 and b = 13
V = 1/3 (1/2×12×13)×15
V = (1/3×1/2×12)×13×15
V = 2×13×15 = 30×13 = 390 in^3

6 0

3 years ago

Could someone help me step by step with this question?

a_sh-v [17]

$\frac{2}{3}(9+x)=-5(4-x) \\ \\ 3*\frac{2}{3}(9+x)=3*[-5(4-x)] \\ \\ 2(9+x)=-15(4-x) \\ \\ 18+2x=-60+15x \\ \\ -13x=-78 \\ \\ \cfrac{-13x}{-13} = \cfrac{-78}{-13} \\ \\ x=6$

7 0

3 years ago

What is it called when the numerator is bigger than the denominator

Aleonysh [2.5K]

Improper fraction :)

3 0

2 years ago

A student found the product of 6 x 10^5 and 5 x 10^6 to be 3 x 10^11. What is the error? What is the correct product? Complete t

Rainbow [258]

The student is off by a power of 10

The answer is 3 x 10^12

3 0

3 years ago

1. Jackson has 75¢ in dimes, d, and nickels, n, in his pocket. Which equation could be solved to find the possible combinations

SpyIntel [72]

Answer:

Part 1) Option D $75=10d+5n$

Part 2) Option B $(4, -2), (0, -1), (-4, 0)$

Part 3) Option A $50=2LW$

Part 4) Option A Ms. Monti bought $4$ adult tickets and $3$ children’s tickets

Part 5) Option D The kitten weighed $14$ ounces when it was $4$ weeks old

Step-by-step explanation:

Part 1)

we know that

$1\ dime=\$0.10$

$1\ nickel=\$0.05$

Let

d-------> the number of dimes

n-----> the number of nickels

so

$0.10d+0.05n=0.75$

Multiply by $100$ both sides

$10d+5n=75$

Part 2)

we have

$y=(-\frac{1}{4})x-1$

To calculate the solutions of the equation for an x value, substitute the value of x in the equation and find the value of y

For $x=4$ -----> $y=(-\frac{1}{4})(4)-1=-2$ ----> $(4,-2)$

For $x=0$ -----> $y=(-\frac{1}{4})(0)-1=-1$ ----> $(0,-1)$

For $x=-4$ -----> $y=(-\frac{1}{-4})(4)-1=0$ ----> $(-4,0)$

Part 3)

we know that

The perimeter of a rectangle is equal to

$P=2(L+W)$

we have

$P=50\ ft$

substitute

$50=2(L+W)$ ------> $50/2=(L+W)$ -----> $50=2L+2W$

Par 4)

Let

x------> the number of adult tickets

y------> the number of children tickets

we have

$25x + 15y = 145$

The ordered pair $(4,3)$ represent

$x=4\ adult\ tickets$

$y=3\ children\ tickets$

therefore

Ms. Monti bought $4$ adult tickets and $3$ children’s tickets

Part 5)

Let

x------> the number of weeks after it was born

y-----> the kitten’s weight in ounces

we have

$y=2.5x+4$

The ordered pair $(4,14)$ represent

$x=4\ weeks$

$y=14\ ounces$

therefore

The kitten weighed $14$ ounces when it was $4$ weeks old

8 0

3 years ago