Answer:
The slope of the given line 1 is -4/5.
The slope of the given line 2 is 0.
The line 2 has a greater slope then line 1.
Step-by-step explanation:
The slope of a line with points (x1,y1) and (x2,y2) is given as:
![m = \frac{y_2- y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_2-%20y_1%7D%7Bx_2-x_1%7D)
Now, Here the, points of the line 1 are A (-2,7) and B (3,3)
So, here, the slope of line AB is ![m = \frac{3 -7}{3-(-2)} = \frac{-4}{3 +2} = \frac{-4}{5}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B3%20-7%7D%7B3-%28-2%29%7D%20%20%3D%20%5Cfrac%7B-4%7D%7B3%20%2B2%7D%20%3D%20%20%20%5Cfrac%7B-4%7D%7B5%7D)
Hence, the slope of the given line 1 is -4/5.
Now, Here the, points of the line 2 are P (5,1) and Q (9,1)
So, here, the slope of line PQ is ![m = \frac{1-1}{9-5} = \frac{0}{4} = 0](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B1-1%7D%7B9-5%7D%20%20%3D%20%5Cfrac%7B0%7D%7B4%7D%20%3D%20%20%200)
Hence, the slope of the given line 2 is 0.
Now, as we can see 0 > ( -4 / 5)
So, the line 2 has a greater slope then line 1.