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3 years ago

Indicate how you might prepare acetic acid from ethene

1 answer:

8 0

Acetic acid can be prepared from ethane by oxidizing it. Acetic acid is generally a carboxylic acid. These acids can be made by the oxidation of alcohols using potassium dichromate(VI) solution with sulfuric acid. Ethane is made into acetic acid in two steps. First it is formed into an aldehyde and then to acetic acid.

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Which statement accurately describes a P wave?

Snowcat [4.5K]

Answer:

A P wave can move through solid rock only. P wave can travel through liquid accurately describes a P wave.

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3 years ago

Hat type of cells carry the oxygen and CO2 in your body?

Diano4ka-milaya [45]

The protein inside red blood cells that carries oxygen to cells and carbon dioxide to the lungs is hemoglobin.

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3 years ago

A 75 um thick polysulphone microporous membrane has an average porosity of E 0.35. Pure water flux through the membrane is 35 m'

Paul [167]

Explanation:

The given data is as follows.

Water flux, $J_{w}$ = 25 $m^{3}/m^{2}h$

= $\frac{25}{3600} m^{3}/m^{2}h$

So, let velocity (u) = $\frac{25}{3600}$ m/s = $6.9 \times 10^{-3}$

$\rho$ = 998 $kg/m^{3}$

Pore size, d = $0.8 \times 10^{-6} m$

$\mu$ = 0.9 cP = $9 \times 10^{-4}$ Pa.s

Hence, calculate the reynold number as follows.

$R_{e} = \frac{\rho \times u \times d}{\mu}$

= $\frac{998 kg/m^{3} \times 6.9 \times 10^{-3} \times 0.8 \times 10^{-6} m}{9 \times 10^{-4} Pa.s}$

= $612.1 \times 10^{-5}$

= 0.006

This means that the flow is laminar.

Now, we use Hagen-Poiseuille equation as follows.

$J_{w} = \frac{\varepsilon \times d^{2}}{32 \times \mu \times \tau} \times \frac{\Delta P}{L_{m}}$

where, $\varepsilon$ = membrane porosity = 0.35

d = $0.8 \times 10^{-6}$ m

$\Delta P$ = $2 \times 10^{5} Pa$

$\mu$ = $9 \times 10^{-4}$

$\tau$ = tortuosity

$L_{m}$ = membrane thickness = $75 \times 10^{-6} m$

$\frac{25}{3600} = \frac{0.35 \times (0.8 \times 10^{-6})}{32 \times (9 \times 10^{-4}) \times \tau}$

$\tau$ = 3.73

Hence, the tortuosity factor of the pores is 3.73.

As flow resistance = $R_{m}$

$J_{w} = \frac{\Delta P}{r \times R_{m}}$

$R_{m} = 3.2 \times 10^{10} m^{-1}$

Water permeability is represented by $L_{p}$ .

$J_{w} = L_{p} \times \Delta P$

$6.9 \times 10^{-3}$ = $L_{p} \times 2 \times 10^{5} Pa$

$L_{p} = 3.45 \times 10^{-8} m^{3}/m^{2}s Pa$

Therefore, the resistance to flow is $3.2 \times 10^{10} m^{-1}$ and its water permeability is $3.45 \times 10^{-8} m^{3}/m^{2}s Pa$ .

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3 years ago

Dependence definition no more than 7 words

DochEvi [55]

Reliance on something or someone for support.

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3 years ago

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4 years ago

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