Answer:
The Bohr model suggested that electrons orbited the nucleus in circular paths where as the modern model views the atom to consist of positively charged nucleus surrounded by electrons.
Explanation:
In the modern model, the nucleus contains two sub-atomic particles, the protons which are positively charged and the neutrons which are not charged.According to Bohr's model,the electron in a hydrogen atom travel around the nucleus in a circular orbit. In the modern model, electrons do not move around nucleus around circular obits.
<span>Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN</span>⁻(aq)
+ Na⁺<span>(aq).
Chemical reaction 2: CN</span>⁻ +
H₂O(l) ⇄ HCN(aq) + OH⁻<span>(aq).
c(NaCN) = c(CN</span>⁻<span>)
= 0.021 M.
Ka(HCN) = 4.9·10</span>⁻¹⁰<span>.
Kb(CN</span>⁻) = 10⁻¹⁴ ÷
4.9·10⁻¹⁰ = 2.04·10⁻⁵<span>.
Kb = [HCN] · [OH</span>⁻]
/ [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] =
x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M
- x).
Solve quadratic equation: x = [OH</span>⁻<span>] = 0.00198 M.
pOH = -log(0.00198 M) = 2.70.
pH = 14 - 2.70 = 11.3.</span>
Answer:
2-Butene
Explanation:
The first step is the <u>ionization</u> of the acid to produce the hydronium ion. Then the OH will attack this ion to produce a <u>charged species</u> that can be stabilized when <u>H2O is produced</u>.
Then an <u>elimination</u> takes place to produce the more <u>substituted alkene</u> 2-butene and the <u>hydronium ion</u> is gain produced.
Answer: Temperature final = 103 °C
Explanation: To solve for final temperature we use the equation of heat:
Q= mc∆T
Next derive the equation to find final temperature
Q = mc(T final - T initial)
Q / mc = T final - T initial
Transpose T initial and change the sign so that T final will be left.
T final = Q / mc + T initial
Substitute the values:
T final = 305 J / 28.8 g x 0.128 J/(g°C)
= 305 J / 3.6864 J/°C
= 82.7 + 20.0°C
= 103 °C final temperature.
