Answer:
Arc length MK = 15.45 units (nearest hundredth)
Arc measure = 58.24°
Step-by-step explanation:
Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)
ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

where:
is the angle- A is the side adjacent the angle
- H is the hypotenuse (the side opposite the right angle)
Given:
= ∠KLM- A = LN = 8
- H = KL = 15.2



Therefore, the measure of arc MK = 58.24° (nearest hundredth)

Given:
- r = 15.2
- ∠KLM = 58.24313614°


9x^8 is the answer for the problem
Given:
Principal amount = $2000
Rate of interest = 3.5% compounded quarterly.
Time = 6 years
To find:
The amount after 6 years.
Solution:
The formula for amount after compound interest is:

Where, P is principal, r is rate of interest in decimal, n is the number of time interest compounded in an year and t is the number of years.
The interest is compounded quarterly, so
.
Substituting
, we get




Approximate the value to the nearest hundredth.

The amount after 6 years us $2465.10. Therefore, the correct option is A.
To 2 decimal places, the square root of pi is 1.77
The greatest possible area with a fixed length of fencing (perimeter) is a circle.
Circumference = 2 pi x radius = 24 m
Radius = (24 m) / (2 pi) = 12 m / pi
Area of a circle = pi x radius squared = (pi) x (12 m / pi)^2 = 144 / pi = 45.837 square meters.
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The rectangle with the greatest possible area for a fixed perimeter is the square.
Each side of the square = 24 / 4 = 6 meters
Area of a square = (side) squared = 36 square meters
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There is no 'least possible' area. The longer and skinnier you make it,
the less area it will have.
Here are some examples. Each one has 24 m of fencing:
5 m x 7 m = 35 square meters
4 x 8 = 32 square meters
3 x 9 = 27 square meters
2 x 10 = 20 square meters
1 x 11 = 11 square meters
0.5 x 11.5 = 5.75 square meters
0.1 x 11.9 = 1.19 square meters
1 centimeter x 11.99 meters = 0.1199 square meters
1 millimeter by 11.999 meters = 0.011999 square meters
The longer and skinnier the garden is, the less area it has.