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strojnjashka [21]
2 years ago
10

Complete the steps to find the algebraic expression that represents the situation. On my last birthday I weighed 180 pounds. One

year later my weight had decreased by pounds. Write the expression that gives my weight one year later.
Mathematics
1 answer:
rusak2 [61]2 years ago
7 0
Noooooooooooooooooooooooooooooo it’s C because of the because ocean air
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What is the correct solution to 1/2(x+18)=4(2x-6)-9x
elixir [45]

Answer:

x=-22

Step-by-step explanation:

1/2(x+18)=4(2x-6)-9x

Distribute the 4

1/2(x+18)=4(2x)-4(6)-9x

1/2(x+18)=8x-24-9x

Combine like terms

1/2(x+18)=-x-24

Multiply each side by 2

2*1/2(x+18)=2(-x-24)

Distribute

x+18 = -2x-48

Add 2x to each side

x+2x+18 = -2x+2x-48

3x+18 = -48

Subtract 18 from each side

3x+18-18 = -48-18

3x = -66

Divide by 3

3x/3 = -66/3

x = -22

8 0
3 years ago
Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k<br>2<br>-2<br>1/2<br>-1/2
Umnica [9.8K]

Answer:

Step-by-step explanation:

Using the graph we can notice something

let's take the abscissa  -2 and -4

  • the ordinate that goes with -2 using g is 0
  • the ordinate that goes with  -4 using f is 0

so we can say that :

f(-4)=g(-2)

wait we khow that g(x)=f(k*x)

so x= -2 then let's replace it in the expression : f(k*x)

we get f(-4)=g(-2)=f[k*(-2)]

let's solve the equation: -2k = -4

                                               k = -4/-2

                                                k=2

so finally we get k=2

let's check :

from the graph we get :

  • f(-2)=2
  • g(-1)=2

we have (-1)*2 = -2

so it is true

3 0
3 years ago
Consider the following equation f(x)=(x^2+4)/(4x^2-4x-8)
kifflom [539]

<em><u>Question:</u></em>

Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)

<em><u>Answer:</u></em>

The vertical asymptotes are x = 2 or x = -1

<em><u>Solution:</u></em>

Given that,

f(x)=\frac{x^2+4}{4x^2-4x-8}

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation

4x^2-4x-8=0\\\\Divide\ by\ 2\\\\x^2 - 2x - 4 = 0

Split\ the\ middle\ term\\\\x^2+x-2x-2=0\\\\Group\ the\ equation\\\\(x^2 + x) - (2x + 2) = 0\\\\Factor\ the\ common\ term\\\\x(x + 1) - 2(x + 1) = 0\\\\(x + 1)(x - 2) = 0\\\\Therefore,\\\\x + 1 = 0\\\\x = -1\\\\And\\\\x - 2 = 0\\\\x = 2

Thus the vertical asymptotes are x = - 1 and x = 2

3 0
3 years ago
Read 2 more answers
One integer is 8​ times another. if the product of the two integers is 288, then find the integers.
Anarel [89]
One integer is x
another integer is y

x=8y
xy=288

(8y)(y)=288
8y^2=288
Divide both sides by 8
y^2= 36
The square root of 36 is 6
y=6

x=8y = 8(6) = 48
x=48
7 0
3 years ago
11. Use an inequality symbol (&lt;, &gt;, 2, =) to compare -26
svetlana [45]

Answer:

c. <

Step-by-step explanation:

-26 < (less than) 54

8 0
2 years ago
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