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Nana76 [90]
3 years ago
15

Solve cx + d = ex + f for x

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
5 0

Answer:

x= (f-d)/(c-e)

Step-by-step explanation:

cx + d = ex + f

Collecting Like Terms

cx - ex = f - d

x(c - e) = f - d

x= (f-d)/(c-e)

Scrat [10]3 years ago
4 0

Answer:

Step-by-step explanation:

cx + d = ex + f

Making x as subject

cx - ex = f - d

x(c - e) = f - d

Dividing by (c - e)

x = (f - d)/(c - e)

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Solution as ordered pair is:

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Step-by-step explanation:

Solving the system of equations:

3x+2y=56\,\,\,(1)\\9x-2y=4\,\,\,(2)

Adding equation(1) and equation(2)

3x+2y=56\\9x-2y=4\\--------\\12x=60\\x=\frac{60}{12}\\x=5

Putting value of x i.e x=5 in equation(1)

3x+2y=56\\3(5)+2y=56\\ 15+2y=56\\2y=56-15\\2y=41\\y=\frac{41}{2}\\y=\frac{41}{2}

So, value of x=5 and y=\frac{41}{2}

Solution as ordered pair is:

(5,\frac{41}{2})

Keywords:System of Equations

Learn more about System of Equations at:

  • brainly.com/question/6075514
  • brainly.com/question/7490805
  • brainly.com/question/13168205

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At 4 p.m., the temperature started to change drastically. Each hour, for three hours the temperature decreased by 7°F
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Answer:

\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}

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