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BaLLatris [955]
2 years ago
15

Help with math please. Thx

Mathematics
1 answer:
REY [17]2 years ago
7 0
(8 x 1)4 + (2 x 1)2 = 32 ft2
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Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.
SpyIntel [72]

Let

x------> the number of multiple choice question

y------> the number of free response question

we know that

3x+8y=55 -----> equation A

x+y=15

x=15-y -----> equation B

Substitute equation B in equation A

3[15-y]+8y=55

45-3y+8y=55

5y=55-45

5y=10

y=2

Find the value of x

x=15-y

x=15-2=13

therefore

<u>the answer is</u>

the number of multiple choice question are 13

the number of free response question are 2

5 0
3 years ago
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A woman is looking for a biker square office. She finds at office twice the area of her current office. If the perimeter of her
MatroZZZ [7]

Answer:

968

Step-by-step explanation:

Current office length = 22

22 * 22 = 484

484 * 2 = 968

8 0
2 years ago
Read 2 more answers
The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g
Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 \\ n \geq 30. Mathematically

\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean \\ \mu = 0 and a population standard deviation \\ \sigma = 1.

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}} [2]

From the question, we know that

  • The population mean is \\ \mu = 88 WPM
  • The population standard deviation is \\ \sigma = 14 WPM

We also know the size of the sample for this case: \\ n = 137 sixth graders.

We need to estimate the probability that a sample mean being greater than \\ \overline{X} = 89.87 WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}

\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}

\\ Z = 1.5634 \approx 1.56

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that \\ P(\overline{X} < 89.87). Then

\\ P(z

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

\\ P(z>1.56) = 1 - P(z

\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

5 0
3 years ago
Co-payment is 20% of $23,890 , her co-payment is
Sidana [21]

the answer to the question is 4,778

3 0
3 years ago
Find the surface area of the cylinder
Alik [6]

Answer:

Surface Area = 282.6 cm²

Step-by-step explanation:

Formula: SA = 2\pirh + 2\pir²

SA = 2\pirh + 2\pir²

SA = 2(3.14)(5)(4) + 2(3.14)(5)

SA = 2(3.14)(5)(4) + 2(3.14)(25)

SA = 125.6 + 157

SA = 282.6 cm²

4 0
3 years ago
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