Answer:
17.5%
Step-by-step explanation:
First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.
There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.
First, I'll calculate the probability for 15 success, given 30 trials.
30c15*0.4^15*0.6^15
Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)
Check the picture below.
well, since the triangle is an isosceles, with twin sides and twin angles at the "base", let's check what the angle at R is, 15(7) - 31 = 74, and her twin sister at T is also 74, that means that the angle at S is 180 - 74 - 74 = 32.
3 / 5 = (x+1) / (y-2)
↓
↓ multiply by 5 / 3
↓
1 = 5 * (x+1) / 3 * (y-2)
↓
↓ move and simplify
↓
5x + 5 = 3y - 6
↓
↓ minus 5
↓
5x = 3y - 11
↓
↓ divide by 5
↓
Answer : x = (3y - 11) / 5
Answer:
56 + 7d
Step-by-step explanation:
For using the distributive property, You have to multiply the first number to the rest. So 8 x 7 = 56 and 7 x d = 7d.
First one:
The circumference of the whole circle is (2π x the radius),
and 60° is (60/360) = 1/6 of the whole circumference.
Second one:
The area of the whole circle is (π x the radius²), and
the 40° sector is (40/360) = 1/9 of the whole area.
I hope this is enough help.
