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3 years ago

Three coins are tossed. What is the probability that two land on heads?

1 answer:

7 0

<span>Before you begin, you need to assume some things about the coins for this problem to be solvable. These assumptions are natural, but they are ESSENTIAL as well, so you shouldn't make them without realizing it.

#1) You have to assume the outcomes on each coin flip are independent. (Our understanding of the physics of coin flipping easily justifies this assumption.) the answer is 1/2

#2) You must assume something about the probability of heads on each of the three coins. The usual assumption is that there is a 50% chance of heads on each toss of each coin.
</span>

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4. If A is at (4, -1) and B is at (2,-7), find the midpoint of segment AB.

melomori [17]

The answer is (3,-4). On a graph you see it is right in the middle. Hope this helps.

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3 years ago

Which veal represents the functions ?

sammy [17]

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3 years ago

The United States has a total area of 3,796,742 square miles.

Dvinal [7]

Answer:

4 * 10^6

Step-by-step explanation:

3,796,742 is about 4,000,000

4 * 10^? = 4,000,000

4 to 4,000,000 is an extra 6 zeroes

? = 6

4 * 10^6

4 0

3 years ago

Find the distance between the two given points. (-6, -5) and (2, 0)

Ipatiy [6.2K]

Answer:

The answer is

<h2> $\sqrt{41} \: \: or \: \: \: 6.403 \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{( {x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-6, -5) and (2, 0)

The distance is

$d = \sqrt{ ({ - 6 - 2})^{2} + ({ - 5 - 0})^{2} } \\ = \sqrt{ ({ - 4})^{2} + ({ - 5})^{2} } \\ = \sqrt{16 + 25} \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

$\sqrt{41} \: \: or \: \: \: 6.403 \: \: \: units$

Hope this helps you

4 0

3 years ago

A flow meter is attached in a hydraulic line that measures 18 gal/min. The line has an inside diameter of 1.0 in. What is the fl

snow_tiger [21]

The flow velocity measured as in/min at the meter is 5924.13 in/min

<h3 /><h3>Volumetric flow rate</h3>

We know that the volume flow rate Q = Av where

A = cross-sectional area of pipe and
v = flow velocity

Now, Q = 18 gal/min

Converting this to in³/min, we have

Q = 18 gal/min = 18 × 1 gal/min = 18 × 231 in³/min = 4158 in³/min

A = πd²/4 where d = diameter of pipe = 1.0 in.

<h3 /><h3>Flow velocity, v</h3>

Since Q = Av, making v subject of the formula, we have

v = Q/A

v = 4Q/πd²

Substituting the values of the variables into the equation, we have

v = 4Q/πd²

v = 4 × 4158 in³/min ÷ π × (1.0 in)²

v = 16632 in/min ÷ π

v = 5924.13 in/min

So, the flow velocity measured as in/min at the meter is 5924.13 in/min

Learn more about flow velocity here:

brainly.com/question/15648466

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2 years ago