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3 years ago

13

Pleaseee someone help me TEST TOMORROW

1 answer:

zubka84 [21]3 years ago

5 0

3.A

4.c

5. A

please name me brainliest

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A branch falls from a tree how fast is the branch moving after drug .28 seconds

alexdok [17]

Acceleration=9.81m/s^2
initial velocity=0m/s
time=.28s

We have to find final velocity.

The equation we use is

Final velocity=initial velocity+acceleration x time

Vf=0m/s+(9.81m/s^2)(.28s)
Vf=2.7468m/s

We would round this to:

Vf (final velocity)=2.7m/s

6 0

3 years ago

Waves from a radio station have a wavelength of 369 m. They travel by two paths to a home receiver 20.0 km from the transmitter.

Olenka [21]

Answer:

92.25m

Explanation:

In order to solve the exercise, it is necessary to apply the concept of construtive interference due to a path difference.

The formula is given by,

$\delta = (m+\frac{1}{2})\frac{\lambda}{n}$

where,

n is the index of refraction of the medium in which the wave is traveling

$\lambda =$ wavelenght

$\delta =$ is the path difference

m = integer (0,1,2,3...)

Since in this case we are dealing with an atmospheric environment, where air is predominant, we approximate n to 1.

And since we need the reflected wave,

$\delta = 2x$

Where x is the distance in one direction without return.

The distance must correspond to the minimum therefore m = 0, so

$\delta = (m+\frac{1}{2})\frac{\lambda}{n}$

$\delta = ({0+\frac{1}{2})\frac{369}{1}$

$\delta = 184.5m$

Then the minimum distance is:

$x= \frac{delta}{2}$

$x = \frac{184.6}{2}$

$x = 92.25m$

Therefore the minimum distance from the mountain to the receiver that produces destructive interference at the receiver is 92.25m

5 0

3 years ago

An object experiences a 8.9 N force and accelerates 6 m/sec2. What is the object's

Inessa [10]

b stupidrwfs

planation:

3 0

3 years ago

Not a question but need a lot of tips

skad [1K]

DibujaZos da buenos tips e incluso el pinta con colores faber castel son económicos y el dibujo queda epico

8 0

3 years ago

A ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-T uniform magnetic field oriented so that th

inysia [295]

Answer:

The magnitude of the average emf induced in the coil is approximately o.32 V.

Explanation:

As, no. of loops = N = 10

Area = 0.23 m^2

Magnetic field = B = 0.047 T

Δt = 0.34 s

These are the given things now we have to find the EMF. So the formula of emf is:

emf = e = N×ΔФ/Δt

Therefore, ΔФ = B . ΔA = BΔAcos(θ)

Since, flux is maximum so θ = 0 and cos(0) = 1

Then,

ΔФ = BA

e = N×(BΔA)/Δt

e = 10×(0.047×0.23)/0.34

e = 0.317 V.

So, we can write it by rounding off the digit

e ≅ 0.32 V.

5 0

3 years ago