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Taya2010 [7]
2 years ago
6

A woman carries a 10kg box up a set of 5m high stairs and then down a 12m long hallway. How much work does she do on the box?

Physics
1 answer:
nika2105 [10]2 years ago
7 0

Answer: 1666J

Explanation:

Given that,

Mass of box (m) = 10kg

Total distance covered by box (h)

= (5m + 12m)

= 17m

work done on the box = ?

Work is done when force is applied on an object over a distance. Hence, the magnitude of work done on the box depends on its mass (m), distance covered (h), and acceleration due to gravity (g)

(g has a value of 9.8m/s²

i.e Work = mgh

Work = 10kg x 9.8m/s² x 17m

Work = 1666J

Thus, 1666 joules of work was done by the woman on the box.

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A single conservative force Fx = (6.0x  12) N (x is in m) acts on a particle moving along the x axis. The potential energy asso
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Answer:

U(3)=-43J

Explanation:

Potential energy is minus the integral of Fdx.  Doing the integration yields:

U=\int\limits {6.0x+12}\, dx

U=-3x^2-12x+C

U(0)=20J

so

U(0)=-3(0)^2+12(0)+C=20

C=20

Now for x=3.0m

U(3)=-3*(3)^2-12(3)+20

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A hockey player applies an average force of 80.0 N to a
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Answer:

Impulse =  8.0Ns

Explanation:

Given

Force = 80.0N

Mass = 0.25kg

Time = 0.10s

Required

Determine the impulse

The impulse is calculated as follows:

Impulse =  Force * Time

Substitute values for Force and Time

Impulse =  80.0N * 0.10s

Impulse =  8.0Ns

<em>Hence, the impulse experienced is 8.0Ns</em>

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Microwave ovens emit microwave energy with a wavelength of 12.5 cm. What is the energy of exactly one photon of this microwave r
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The energy of exactly one photon of this microwave radiation is 1.59 × 10⁻²⁴Joule

<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

\large {\boxed {E = h \times f}}

<em>E = Energi of A Photon ( Joule )</em>

<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>

<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}

\large {\boxed {E = qV + \Phi}}

<em>E = Energi of A Photon ( Joule )</em>

<em>m = Mass of an Electron ( kg )</em>

<em>v = Electron Release Speed ( m/s )</em>

<em>Ф = Work Function of Metal ( Joule )</em>

<em>q = Charge of an Electron ( Coulomb )</em>

<em>V = Stopping Potential ( Volt )</em>

Let us now tackle the problem!

<u>Given:</u>

λ = 12.5 cm = 12.5 × 10⁻² m

<u>Unknown:</u>

E = ?

<u>Solution:</u>

E = h f

E = h \frac{c}{\lambda}

E = 6.63 \times 10^{-34} \frac{3 \times 10^8}{12.5 \times 10^{-2}}

\large {\boxed {E = 1.59 \times 10^{-24} ~ Joule } }

<h3>Learn more</h3>
  • Photoelectric Effect : brainly.com/question/1408276
  • Statements about the Photoelectric Effect : brainly.com/question/9260704
  • Rutherford model and Photoelecric Effect : brainly.com/question/1458544
  • Photoelectric Threshold Wavelength : brainly.com/question/10015690

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt

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