What is the distance formula? in trigonometry

Mathematics

1 answer:

NISA [10]3 years ago

8 0

Answer:

In trigonometry the distance formula is used to find the distance between any two points.

The formula is given by

$d=\sqrt{(x_2-x_2)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Distance formula is used to find the distance between two points.

Let us suppose, there are two points A and B in xy- plane whose coordinates are

$A(x_1,y_1),B(x_2,y_2)$

If d is the distance between these two points then the distance between A and B can be find using the below formula

$d=\sqrt{(x_2-x_2)^2+(y_2-y_1)^2}$

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So, I undestood slope right. But, I get confused with the other points that intersect there is multiple of them. How do i look f

ivanzaharov [21]

Answer:

slope = 2

Step-by-step explanation:

Find 2 points on the line that land perfectly on the grid. I'll choose these 2 here:

(-2, -1) and (0, 3)

Rise is the change in the y value from one point to the other, and run is the change in the x. Looking at these 2 points, y went from -1 to 3. That is a <em>rise</em> of 4. The x went from -2 to 0, so that is a <em>run</em> of 2. "rise over run" means rise literally over run in a fraction like this:

$m=\frac{rise}{run}$

The more proper way to calculate slope looks like this, but it's really the same thing in the end:

$m=\frac{y2-y1}{x2-x1}$

where (x1, y1) and (x2, y2) are your 2 points.

Finally, the slope of this line is:

$m=\frac{3--1}{0--2}\\\\m=\frac{4}{2}\\\\m=2$

That's a rise of 4 over a run of 2, and that simplifies to just a slope of 2.

8 0

3 years ago

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

Leviafan [203]

$4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\ sin^{2} x= \frac{3}{4} \\ sinx= \pm \sqrt{ \frac{3}{4} } \\ sinx= \frac{ \sqrt{3} }{2} \ or \ sinx=- \frac{ \sqrt{3} }{2} \\ x= \frac{ \pi }{3} , \ \frac{2 \pi }{3} , \ \frac{4 \pi }{3} , \ \frac{5 \pi }{3}$