2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Step-by-step explanation:
The given is,
Initial investment - $5000
Future amount - $6000
Interest rate - 7.5% (compounded quarterly)
Step:1
Formula to calculate the Future amount with compound interest,
...................................(1)
Where, F - Future amount
P - Initial amount
r - Rate of interest
n - No. of compounding in a year
t - Time period
From given,
F = $6000
P = $5000
r = 7.5%
n = 4 (compounded quarterly)
Equation (1) becomes,



Take log on both sides,

Substitute log values,
0.07918 = 4(t) (0.0080676)
= (t) (0.0322705)
= 2.45
t ≅ 2.5 years
Result:
2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Answer:
78
Step-by-step explanation:
QT is a 180 straight line so 180-55-47
Hope its right!
Answer:
addition and multiplication
Step-by-step explanation:
add 4.5 + 1.5 to get 6 ft and then multiply that by 7
5/12+5/12=10/12
10/12+10/12=20/12 wich =1.666666666666667theres ur answer to one.
dont know the answer to the other one
Sorry
Hope that helps
The expected number out of 1000 selected college seniors that completed 1 job application through the career
centers is given by 0.011 x 1000 = 11 which is close to 14.
The expected number out of 1000 selected college seniors that completed 2 job application through the career
centers is given by 0.115 x 1000 = 115 which is far away from 15.
The expected number out of 1000 selected college seniors that completed 3 job application through the career
centers is given by 0.123 x 1000 = 123 which is close to 130.
Therefore, the result that would be suprising is "15 seniors completed 2 job applications through the career
center."