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ozzi
3 years ago
14

How can adding doubles help you multiply by 2? give an example

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
It helps you multiply by two by giving you the answer to the expression.
Example: 2•5=10/
katovenus [111]3 years ago
7 0
I was gonna say what he was gonna say up lol
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write the equation of the line perpendicular of the graph of y=-1/4x+3 and passes through the point (-2,4)
Dafna11 [192]
Y=4x+12, I Hope this helps you!

6 0
2 years ago
Which option is equivalent to log 7 - log 2? A. log 5 7 B. log O C. log 9 OD. log 72​
svetoff [14.1K]

Answer:

la vida mafio

Step-by-step explanation:

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7 0
3 years ago
In a cricket match, Rajat scored thrice as many runs as Devansh.
Rina8888 [55]

Answer:

let jivesh score x runs so rajat scores 3x runs

total runs = 300-8 = 292 runs

so x+3x = 292

4x = 292

x = 292/4

x = 73

so jivesh score 72 runs and rajat scores 216 runs

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Given:
pychu [463]
We can use the SSS congruence theorem to prove that the two triangles in the attached figure are congruent. The SSS or side-side-side theorem states that each side in the first triangle must have the same measurement or must be congruent on each of the opposite side of another triangle. In this problem, for the first triangle, we have sides AC, CM, AM while in the second triangle we have sides BC, CM, and BM. By SSS congruent theorem, we have the congruent side as below:
AC = BC
CM = CM
AM = BM 

The answer is SSS theorem.
4 0
2 years ago
Read 2 more answers
In 1990, California switched from a 6/49 lottery to a 6/53 lottery. Later, the state switched again to a 6/51 lottery. (a) Find
zalisa [80]

Answer:

(a) 9.9321*10^{-11}

(b) 6.0498*10^{-11}

(c) 7.7120^{-11}

(d) 1.6417 times more probable

Step-by-step explanation:

(a) The probability of winning a 6/49 lottery is given by:

P = \frac{1}{49*48*47*46*45*44} =9.9321*10^{-11}

(b) The probability of winning a 6/53 lottery is given by:

P = \frac{1}{53*52*51*50*49*48} =6.0498*10^{-11}

(c) The probability of winning a 6/51 lottery is given by:

P = \frac{1}{51*50*49*48*47*46} =7.7120^{-11}

(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:

r=\frac{9.9321*10^{-11}}{6.0498^{-11}}\\r=1.6417

It is 1.6417 times more probable.

8 0
3 years ago
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