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ozzi
3 years ago
14

How can adding doubles help you multiply by 2? give an example

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
It helps you multiply by two by giving you the answer to the expression.
Example: 2•5=10/
katovenus [111]3 years ago
7 0
I was gonna say what he was gonna say up lol
You might be interested in
Help me please....
KIM [24]

Answer:

car a-50 kilos per hour

car b-55 kilos per hour

car b is faster

Step-by-step explanation:

150/3=50

220/4=55

3 0
3 years ago
Sam wants to buy 8 pencils and 6 pens, which cost a total of $8.50. He realizes he doesn't have enough cash and instead takes on
Diano4ka-milaya [45]
X = pencils, y = pens

8x + 6y = 8.50
4x + 4y = 5.....multiply by -2
----------------
8x + 6y = 8.50
-8x - 8y = -10 (result of multiplying by -2)
-----------------add
-2y = - 1.50
y = -1.50 / -2
y = 0.75 <=== pens cost 0.75

4x + 4y = 5
4x + 4(0.75) = 5
4x + 3 = 5
4x = 5 - 3
4x = 2
x = 2/4
x = 0.50 <== pencils cost 0.50
8 0
3 years ago
Solve for d 6d -11/2 = 2d -13/2. Please answer quickly
Slav-nsk [51]

6d -11/2 = 2d -13/2

Subtract 2d from both sides

6d -11/2 - 2d = 2d -13/2 - 2d

Simplifying

4d -11/2 = -13/2

Add 11/2 to both sides

4d -11/2 + 11/2 = -13/2 + 11/2

Simplifying

4d = -2/2

4d = -1

Divide both sides by 4

4d/4 = -1/4

Simplifying

d = - 1/4

7 0
3 years ago
Read 2 more answers
Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa
barxatty [35]

z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}

We're given that f_x(6,1)=3 and f_y(6,1)=-1, and want to find \frac{\partial z}{\partial v}(1,2).

By the chain rule, we have

\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}

and

\dfrac{\partial x}{\partial v}=2v

\dfrac{\partial y}{\partial v}=-1

Then

\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)

(because the point (x,y)=(6,1) corresponds to (u,v)=(1,2))

\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}

4 0
3 years ago
Can someone help please, will give brainiest if correct!!!!
Bond [772]

Answer:

AB = 9/2 cm

AB = 4.5 cm

Step-by-step explanation:

The area of small rectangle

x * (x-4) = x^2 -4x

The area of  the big rectangle

The height is 2x +x  and the width is x-2

(2x+x) * (x-2)

(3x) * (x-2)

3x^2 -6x

Add the areas together

x^2 -4x + 3x^2 -6x

4x^2 -10x

This is equal to 36

4x^2 -10x=36

Subtract 36 from each side

4x^2 -10x -36=36-36

4x^2 -10x-36=0

Divide each side by 2

2x^2 -5x -18=0

Factor

(x + 2) (2 x - 9) = 0

Using the zero product property

x+2=0  2x-9=0

x = -2   2x =9

x = -2   x = 9/2

Since we cant have a negative length

x = 9/2

AB = 9/2 cm

5 0
3 years ago
Read 2 more answers
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