Answer:
In the question 4/0, the denominator is zero so it is not a rational number.
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
A: ∠3 and ∠2
E: Since ∠3 and ∠2 lie on the same line and on a straight line, they must be supplementary as they must add up to 180° to satisfy the condition of a straight line.