If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
Answer:
b
Step-by-step explanation:
2×5=10 very simple becausevthe equation is e Wii als 0
Answer:
70
Step-by-step explanation:
Angle Q and angle P are supplementary angles, so they add up to 180 degrees.
6x + 4 + 10x = 180
16x + 4 = 180
16x = 176
x = 176/16
x = 11
Put x in angle Q as 11 and solve.
6(11) + 4
66 + 4
= 70
Angle Q measures 70 degrees.
U should add all the #s together so... it = 11.3
then divide by the # of terms. so...... 11.3/ 14= 0.9357 (rounded makes 0.94)
So .... B
