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geniusboy [140]
3 years ago
9

Find the number that is 2/3 of the way from 3/4 to 3 5/12

Mathematics
1 answer:
lana66690 [7]3 years ago
6 0
I got 2.527. And the 7 repeats I’m wasn’t sure if you wanted it in a fraction but it shouldn’t be difficult to convert if you have a calculator with that function
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What is the common difference of 31, -169, -369, -569?
san4es73 [151]

Answer:

31 is a positive number, while -169, -369, and -569 is negative.

Step-by-step explanation:

Negative numbers, are numbers less then 0 and include a negative sign that looks like this "-".

Positive numbers are numbers above 0 and don't include a negative sign.

-169, -369, and -569 is negative because they have a negative symbol and the number is below 0, while 31 is positive because it's above 0 and doesn't include a negative sign.

4 0
3 years ago
The expression 5(x+24) shows the total amount of money they spent. Expand the expression using the Distributive Property.
Kobotan [32]

\huge\boxed{Hi!}

Distribute 5 using the Distributive Property:

5(x+24)

Multiply 5 by x:

5x

Multiply 5 by 24:

120

Now, add the products:

5x+120 (Answer)

Hope it helps! Enjoy your day :)

~Just a determined teen

\bf{erutaNtneliS

4 0
2 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
Find the volume of the prism.
umka21 [38]

Answer:

C = 210cm^3

Step-by-step explanation:

We can get an estamate when we use the equation L x H x W = x/2

This shows 8 x 8 x 7,  then divide by 2 = 224cm^3

The reason it is slightly less could be the facts the teachers want you to remember this one.

For right side prism the equation is (1/2)b x h x  H

which means;

The volume of a triangular prism can be found by multiplying the base times the height. Both of the pictures of the Triangular prisms below illustrate the same formula. The formula, in general, is the area of the base (the red triangle in the picture on the right) times the height,h.

We use the side and base that surrounds the right side as (1/2)base and as side to find area then use the H as the height being the 7.

3 0
3 years ago
Read 2 more answers
Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples
zheka24 [161]

Answer: a. 0.40   b. 0.23  c . 0.435   d . 0.25

Step-by-step explanation:

                                   melanin      content    Total

                                            high   low

moisture   high                     13      10                23

content    low                       47      30                77

 Total                                   60      40              <u> </u><u>100</u>

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)=\dfrac{40}{100}=0.40

b) Total skin samples has high moisture content = 13+10=23

P(B) =\dfrac{23}{100}=0.23

c) A ∩ B =  Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) =\dfrac{10}{100}=0.10

Using conditional probability formula , P (A|B)=\dfrac{P(A\cap B)}{P(B)}

P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435

d)  P (B|A)=\dfrac{P(A\cap B)}{P(A)}

P (B|A)=\dfrac{0.10}{0.40}=0.25

8 0
3 years ago
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