After demonstrating the procedure by algebraic means, the expression ![(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )](https://tex.z-dn.net/?f=%282%5Csqrt%5B3%5D%7B12%7D%20%29%5Ccdot%20%283%5Csqrt%5B3%5D%7B2%7D%20%29)
<em>is equivalent to</em> ![6\cdot \sqrt[3]{24}](https://tex.z-dn.net/?f=6%5Ccdot%20%5Csqrt%5B3%5D%7B24%7D)
.
In this question we proceed to <em>simplify</em> by <em>algebraic</em> means into a <em>single</em> <em>radical</em> expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:
- Given.
-
![(2\cdot 3) \cdot (\sqrt[3]{12} \cdot \sqrt[3]{2} )](https://tex.z-dn.net/?f=%282%5Ccdot%203%29%20%5Ccdot%20%28%5Csqrt%5B3%5D%7B12%7D%20%5Ccdot%20%5Csqrt%5B3%5D%7B2%7D%20%20%29)
Commutative property/ Associative property. - Definition of cubic root/
![\sqrt[n]{a} = \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20%5Csqrt%5Bn%5D%7Bb%7D)
/Result
After demonstrating the procedure by algebraic means, the expression <em>is equivalent to</em> .
To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591
Answer: y = 36x
Step-by-step explanation: Given that x and y vary directly then the equation relating the is
y = kx ← k is the constant of variation
To find k use the condition x = , y = 12, then
k = = = 12 × 3 = 36
y = 36x ← equation of variation
Answer:
$41.16
Step-by-step explanation:
Length of bricks required = 35 feet, length of brick sold = 10 inches, cost of 10 inches brick = $0.98 per brick
Total number of brick required to build the back yard = Length of bricks required ÷ Length of brick sold
1 ft = 12 inches
Number of brick required = (35 * 12) ÷ 10
Number of bricks required = 42 bricks
Cost of brick required = Per length cost of brick * Number of bricks required
Cost of brick required = 0.98 * 42
Cost of brick required = $41.16
Ms. Fontanges would spend $41.16 on the purchase of bricks
Answer:
Can you put a picture?
Step-by-step explanation:
Remember
(ab)/(cd)=(a/c)(b/d)
and
1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=
=
=
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
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