Answer:
hghjghgjh
Step-by-step explanation:
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
Hello There!!
Step-by-step explanation:
You multiply the reciprocal which is 4 by 3 and that is 12.
Another method: 1/4 ÷3 (use KFC) so it is keep 3,flip the fraction so it is 4/1 them change the sign ÷ into multiplication so it is 3×4/1=12. Therefore,the answer is 12.
hope this helps,have a great day!!
~Pinky~
Answer:nobody
Step-by-step explanation:
4x+10y=-13...you have to add the variables that are the same and then subtract the 13 from 0
