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gavmur [86]
4 years ago
12

What is the solution to the equation 3^sqrt (m-4)-3^sqrt(2m+8)=0

Mathematics
2 answers:
Shkiper50 [21]4 years ago
6 0

Answer:

M=-12

Step-by-step explanation:

PtichkaEL [24]4 years ago
4 0

Answer:

No solution.

Step-by-step explanation:

3^{\sqrt{m-4} } - 3^{\sqrt{2m + 8} }=0\\3^{\sqrt{m-4} } = 3^{\sqrt{2m + 8} }, so\\\sqrt{m-4} =\sqrt{2m + 8} \\m-4=2m+8\\2m-m=-4-8\\m=-12, but\\\sqrt{-4-8} =\sqrt{-12} , that \ is \ impossible \ for \ real\ numbers.\\So,\ no\  solution.

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