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insens350 [35]
2 years ago
14

If the perimeter of a circular ground is 308 M find its radius​

Mathematics
2 answers:
alisha [4.7K]2 years ago
8 0

Answer:

<h3>Correct option is</h3><h3>Correct option isA</h3><h3>Correct option isA49m</h3><h3>Correct option isA49mThe circumference of a circular field is 308m</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= </h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7 </h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7 </h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7 ⇒r=49m</h3>

Step-by-step explanation:

<h2 /><h2>If you noticed I'm wrong please comment</h2>
crimeas [40]2 years ago
3 0

Answer:

Correct option is

A

49m

The circumference of a circular field is 308m

Therefore, 2πr=308

⇒r=

2×22

308×7

⇒r=49m

Step-by-step explanation:

here you go

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ycow [4]

Given:

There are given that the zeroes and degrees of the polynomial:

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Explanation:

From the concept of a polynomial:

A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.

Then,

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\begin{gathered} f(x)=(x+2)(x-2)(x-4) \\ f(x)=(x^2-2x+2x-4)(x-4) \\ f(x)=(x^2-4)(x-4) \\ f(x)=x^3-4x^2-4x+16 \end{gathered}

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Answer:

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Step-by-step explanation:

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