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insens350 [35]
2 years ago
14

If the perimeter of a circular ground is 308 M find its radius​

Mathematics
2 answers:
alisha [4.7K]2 years ago
8 0

Answer:

<h3>Correct option is</h3><h3>Correct option isA</h3><h3>Correct option isA49m</h3><h3>Correct option isA49mThe circumference of a circular field is 308m</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= </h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7</h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7 </h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7 </h3><h3>Correct option isA49mThe circumference of a circular field is 308mTherefore, 2πr=308⇒r= 2×22308×7 ⇒r=49m</h3>

Step-by-step explanation:

<h2 /><h2>If you noticed I'm wrong please comment</h2>
crimeas [40]2 years ago
3 0

Answer:

Correct option is

A

49m

The circumference of a circular field is 308m

Therefore, 2πr=308

⇒r=

2×22

308×7

⇒r=49m

Step-by-step explanation:

here you go

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Answer:

She would save £5

Step-by-step explanation:

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40 × £0.02 = £0.80

→ Add the cost of the one folder

£0.80 + £0.70 = £1.50

⇒ Now we know £1.50 is the amount of money it costs for one student, we multiply that by 120 because there are 120 pupils

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3 years ago
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Answer:

Using

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2 years ago
Introduction to the triangle midsegment theorem‼️ can someone help me find BC,DE, and CE please ❓
Tasya [4]

Answer:

Part 1) BC=68\ units

Part 2) DE=36\ units

Part 3) CE=34\ units

Step-by-step explanation:

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

so

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we have

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substitute the given value

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solve for BC

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Part 2) Find the length of  DE

Applying the Midpoint Theorem

DE=\frac{1}{2}AC

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AC=72\ units

substitute the given value

DE=\frac{1}{2}(72)

DE=36\ units

Part 3) Find the length of  CE

we know that

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The point E is the midpoint segment BC

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BC=68\ units

substitute

68=2CE

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Answer:

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