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timofeeve [1]
3 years ago
11

A)line a and line b B)line b and line c C)line b and line d D) line c and line d

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

A)line a and line b is your answer.

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Find the inverse of the linear function y=1/2x+3.
Anni [7]

Answer:

2(x-3) = y

Step-by-step explanation:

y = 1/2 x +3

To find the inverse, exchange x and y and then solve for y

Exchange x and y

x = 1/2y +3

Then solve for 3

Subtract 3 from each side

x-3 = 1/2 y -3+3

x-3 = 1/2 y

Multiply each side by 2

2 (x-3) = 1/2 *2 y

2(x-3) = y

This is the inverse

7 0
3 years ago
Read 2 more answers
Brian parked in a parking garage 4 floors under ground. Herode an elevator up 17
Law Incorporation [45]

Answer:

Floor ride up to = 13 floor

Step-by-step explanation:

Given:

Parking garage = 4 floors under ground

Elevator up-to = 17 floor

Find:

Floor ride up to

Computation:

Floor ride up to = Elevator up-to - Parking garage

Floor ride up to = 17 floor - 4 floor

Floor ride up to = 13 floor

7 0
2 years ago
(Help? Its a True or False Question) The following is the correct way to show the product for 0.453 × 8.1:
BigorU [14]

What is the relationship between RR' and SS'?


8 0
2 years ago
The functions f and g are defined as follows f(x)=5x+3/6x+7 and g(x)= square root sign x^2-4x
telo118 [61]
<span>f(x)=5x+3/6x+7

This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]

If we assume x≠0 ,    f(6/x) = [30 +3x]/ [36 + 7x]

g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
3 0
2 years ago
This trapezium is drawn on a centimetre grid.<br> Find the area of the trapezium.
aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

<u>From </u><u>the</u><u> </u><u>grid</u><u> </u><u>:</u><u>-</u>

\rm\implies Side_1 = 7 \ units

\rm\implies Side_2 = 3 \ units

\rm\implies \perp \ Distance =4  \ units

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times   \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm  Area = 20 \ unit^2}

3 0
3 years ago
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