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DerKrebs [107]
4 years ago
5

Can two numbers have a GCF that is bigger than their LCM? Explain how you know?

Mathematics
1 answer:
pshichka [43]4 years ago
3 0
The answer to this question would be: No, they can't

Greatest common factor biggest possible value is the number value itself. There is no factor that bigger than the number.

But the least common multiple smallest possible value is the number. There is no multiple that smaller than the number.

So it is not possible to have GCF bigger than LCM.

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gizmo_the_mogwai [7]
The area of the rectangle would be 45 m^3
7 0
4 years ago
Read 2 more answers
Po The diameter of a circular fountain in a city park is 28 feet. A sidewalk that is 3.5 feet will be built around the fountain.
jarptica [38.1K]

Answer:

Area of sidewalk = 346.5 ft^2

Bags of concrete = 277

Step-by-step explanation:

The diameter of the circular fountain is 28 ft. Radius = 28 / 2 = 14 ft

The thickness of the sidewalk is 3.5 ft. This means they want to add 3.5 ft to each radius of the fountain.

To find the area of the sidewalk alone, we have to find the area of the sidewalk alone and then subtract it from the area of the sidewalk and fountain.

That is:

A_s = A_{s+f} - A_f

The fountain is circular and its radius is 14 ft. Hence, its area will be:

A_f = \pi r^2

A_f = \pi *14^2 = 616 ft^2

The sidewalk and fountain together also form a circular shape. Their joint radius will be:

R = 14 + 3.5 = 17.5 ft

Hence, the area will be:

A_{s + f} = \pi R^2 \\A_{s + f} = \pi * 17.5 * 17.5 = 962.5 ft^2

Hence, the area of the sidewalk alone will be:

A_s = 962.5 - 616 = 346.5 ft^2

This is the area of the sidewalk.

For every square foot (ft^2), 0.8 bag of concrete will be used. This means that for 346.5 ft^2:

Bags of concrete = 0.8 * 346.5 = 277.2 ≅ 277

At least 277 bags of concrete will be used for the new sidewalk.

5 0
4 years ago
What is the perimeter of the figure to the nearest tenth of a millimeter?
Bogdan [553]

Answer:

i think the answer is C

Step-by-step explanation:

i normally just do length divided by width to figure this out

3 0
2 years ago
Twelve identical cylindrical pop cans are placed in a box. If sand fills the space between the pop cans and the cans and the sid
Masteriza [31]

Answer:

Step-by-step explanation:

I don't see any information on dimensions of the cans or box, so I'll assume the question wants a general solution.

Three steps will result in the volume of sand required to fill the remaining space in the box.

1.  Calculate the volume of a can using the equation for the volume of a cylinder:  Vol = πr²h

2.  Multiply the can volume by 12.  This will give the total volume of the 12 cans in the box.

3.  Calculate the volume of the box:  Volume = (Base)(Width)(Height)

[Make sure the units are the same as those used in calculating the can volume.  E.g., if the can is calculated with cm as the measue, the box dimensions must also be cm]

4.  Subtract the volume of the12 cans (from step 2) from the volume of the box.

The result from 4 will be the volume of sand required to fill the box containing 12 cans.  

I'm not clear why filling the box with sand is important, but perhaps it will absorb any soda released from cans broken when the heavy box is dropped by the person shocked that 12 cans of pop could be so heavy.

4 0
2 years ago
Find the difference between 1/6 and 1/2
andrew11 [14]

Answer:

1/3 OR -1/3

Step-by-step explanation:

1/2 - 1/6 = ?

3/6 - 1/6 = 2/6

2/6 = 1/3

OR

1/6 -1/2 =?

1/6 - 3/6 = -2/6

-2/6 = -1/3

5 0
3 years ago
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