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lbvjy [14]
3 years ago
13

For a fundraiser, a group plans to sell granola bars and bottles of water at the same prices as described in Part A. The group w

ants the income from the fundraiser to be at least $150.
Choose the inequality to show the number of granola bars x and the number of bottles of water y that must be sold.

A. 1.4x + 0.75 y > 150
B. 1.4x + 0.75y ≥ 150
C. 1.4x + 0.75 < 150
D. 1.4x + 0.75 ≤ 150
Mathematics
2 answers:
shutvik [7]3 years ago
6 0

Answer:

100

Step-by-step explanation:

goblinko [34]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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The width of a rectangle is the sum of the length and 1. The area of the rectangle is 20 units. What is the width, in units, of
IRISSAK [1]

Answer:

W=5

Step-by-step explanation:

W=Width=Length + 1

L = Length

Area = Length * Width = 20

Area = L * W = L * (L+1) = 20

Distribute the L:   L^2 + L = 20

Subtract 20 from both sides: L^2 + L -20 = 20-20

Simplify:  L^2+L-20=0

Factor (L-4)(L+5)=0

Solve using the zero property: L-4=0, L=4      L+5=0, L=-5

The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative.   Width is Length + 1 = 5

6 0
3 years ago
Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

Hence, the rate is:

Rate = \triangle T = 0.935042^\circ /cm

3 0
2 years ago
A submarine patrolling the Indian Ocean was situated 800 feet below sea level. If it ascends 275 feet, what is its new position
Delicious77 [7]

Answer:

-525 feet

Step-by-step explanation:

If a submarine was below sea level, that would mean that it would be at an elevation of negative feet down, so if it's 800 feet below sea level, it's elevation would be -800.

to ascend means to rise, so the submarine would be moving +275 feet (going higher, closer to sea level)

so you can make out this equation: -800 + 275

this would equal: -525

6 0
3 years ago
Please help!
n200080 [17]

Answer:

32.5

Step-by-step explanation:

7h+1.50d

step 2: plug in the hours he worked and the amount of deliveries made.

(7x4)+(1.50x3)=32.5

3 0
2 years ago
PLS HELP! URGENT!!!! A circular flower bed is 20 m in diameter and has a circular sidewalk around it that is 3 m wide. Find the
krok68 [10]

Answer: Area of sidewalk is 217m²

Step-by-step explanation:

The formula for determining the area of a circle is expressed as

Area = πr²

Where

r represents the radius of the circle

π is a constant whose value is 3.14

A circular flower bed is 20 meters in diameter.

radius = diameter/2 = 20/2 = 10 meters

Area of the flower bed = 3.14 × 10²

= 314m²

The circular flower bed has a circular sidewalk around it that is 3 meters wide. This means that the total diameter would be

3 + 20 + 3 = 26m

Radius = 26!2 = 13m

Total area = 3.14 × 13² = 530.66m²

Therefore, area of the sidewalk is

530.66 - 314 = 216.66

The area of sidewalk is 217m² to the nearest whole number

6 0
3 years ago
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