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Ne4ueva [31]
3 years ago
9

____ is the struggle between organisms for food, water, and other needs.

Chemistry
2 answers:
LuckyWell [14K]3 years ago
7 0

Answer:

Competition

Explanation:

Competition, is preys, and predators fighting for survival. Whether it be on the african dessert, lions fighting hyenas over territory, or water.

frutty [35]3 years ago
5 0
The answer is competition
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nikklg [1K]

I believe the correct answer would be "It has no energy because it is just sitting there."

I hope this helps! :D

8 0
3 years ago
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Major groups of minerals include _____. oxides and carbonates ions and isotopes inorganics and halides silicates and magnetics
mash [69]
The  major    groups  of  minerals  includes: carbonate   ions  and oxides,  .  In  addition  to   this   three  groups   the    following   are   also  the  major   groups   of    minerals
native   elements
sulfate
sulfides
halides
silicate
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3 0
3 years ago
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How many significant figures are in the measurement 102,400 meters?
RideAnS [48]

Answer:

4

Explanation:

the zeros after 102,4 are not significant.

4 0
3 years ago
A room with dimensions 7.00m×8.00m×2.50m is to be filled with pure oxygen at 22.0∘c and 1.00 atm. The molar mass of oxygen is 32
patriot [66]

Answer:

Mass of O₂ present in the room: 185200 g

185.2 kg

Quantity of O₂ = 5787.5

Explanation:

The ideal gases Law can solved, what is ths mass of O₂ present in the room, or the quantity of O₂ (moles), present in the room.

P . V = n . R . T

P = 1 atm

V = volume of the room

n = moles

R = 0.082 L.atm/mol.K

T = T° in K

T° C + 273 → 22°C + 273 = 295K

Let's find out the volume of the room

7 m . 8 m . 2.5 m = 140 m³

Units of R, are in L, so we must convert m³ to dm³

1dm³ = 1 L

140m³ . 1000 = 140000 dm³

1.4x10⁵L

1 atm . 1.4x10⁵L = n . 0.082 L.atm/mol.K . 295K

(1 atm . 1.4x10⁵L) / (0.082 L.atm/mol.K . 295K)  = n

5787.5 moles = n

molar mass . moles = mass

5787.5 moles O₂ . 32 g/m = 185200 g of O₂

3 0
3 years ago
Give the number of sigma bonds and pi bonds for benzene, c6h6.
beks73 [17]

Answer:

There are 12 sigma bonds and 3 pi bonds in benzene

Explanation:

  • Molecular formula of benzene is C_{6}H_{6}.
  • Here six carbon atoms are joined together through alternative single and double bond forming a six membered cyclic ring.
  • Six hydrogen atoms are attached to six carbon atoms through a single bond.
  • A single bond represents a sigma bond. A double bond consists of a sigma bond and a pi bond.
  • In the Lewis structure of benzene, there are three C-C single bonds, three C=C double bonds and six C-H single bond.
  • Hence there are 12 sigma bonds and 3 pi bonds in benzene
  • Lewis structure of benzene is given below

8 0
3 years ago
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