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In-s [12.5K]
3 years ago
9

How are the orbits of asteroids similar to, or different from planetary orbits?

Chemistry
1 answer:
Strike441 [17]3 years ago
7 0
Aside from banks, what are 2 other places you might be able to borrow
money? And can you help with more questions on my page thank you so much I really appreciate you and everything you do for this app
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The proof that ch4 is a weak acid
boyakko [2]

Answer: because ch4 is not considered a acid they said it is too weak

Explanation:

8 0
3 years ago
Read 2 more answers
1. Which phase change is accompanied by the release of heat? A) H20(s)--> H2O(g) B) H20(l) ->H2O(s) C) H20(l)→ H2O(g) D) H
docker41 [41]

Answer:

B, liquid to solid.

Explanation: Since heat is being released, the particles for H2O would clump up. Heat is basically being taken out.

5 0
3 years ago
Darwin's theorized that three conditions were necessary for natural selection to occur, which of the following is NOT one of the
Mekhanik [1.2K]

Answer:

The correct option is: stable environment

Explanation:

According to the Darwin's theory, natural selection is the concept by which all the small useful variations of traits are preserved.

According to Darwin, there are three <u>necessary and sufficient conditions</u> for the occurrence of natural selection:

1. struggle for existence

2. variation

3. inheritance

These conditions are said to be necessary because if these conditions are not satisfied then natural selection does not occur.

These conditions are said to be sufficient because if these conditions are satisfied, then natural selection will most definitely occur.

8 0
3 years ago
What is the pH of a .000243 M solution of potassium hydroxide solution?
Evgesh-ka [11]
1.03!! Very easy you welcome:)
3 0
3 years ago
Read 2 more answers
A football is inflated to 12psi at 20°C What is the new pressure in the football
Radda [10]

Answer: The new pressure is 3 psi.

Explanation:

Given: P_{1} = 12 psi,         T_{1} = 20^{o}C

P_{2} = ?,          T_{2} = 5^{o}C

Formula used is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi

Thus, we can conclude that the new pressure is 3 psi.

7 0
3 years ago
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