Answer:
$16,363.9
Step-by-step explanation:
16870 x 0.03 = 506.1
16870 - 506.1 =
[ p+9 ]= 11
pretend that there is a +1 in front of the bracket
1 [ p+9 ]= 11
multiply the bracket by 1
(1)(p)=p
(1)(9)=9
p+9=11
move +9 to the other side
sign changes from +9 to -9
need to get p by itself
p+9-9=11-9
p=11-9
answer:
p=2
Answer:
60
Step-by-step explanation:
Let s represent the number of stickers Sophia has. Then the number Ethan has is (2/3)s. The transfer of 16 stickers can be described by the equation ...
(s -16)/(2/3s +16) = 1/2 . . . . . sophia/ethan = 1/2 after the transfer
2s -32 = 2/3s +16 . . . . . . . . .cross multiply
4/3s = 48 . . . . . . . . . . . . . . . add 32-2/3s
s = (48)(3/4) = 36 . . . . . . . . .multiply by 3/4
Together, the total number of stickers held is s +(2/3)s = (5/3)s.
5/3s = (5/3)(36) = 60 . . . . . total of Sophia's and Ethan's stickers
Together, Sophia and Ethan have 60 stickers.
Answer: $57.6
Step-by-step explanation:
Given : A businesswoman sells a bag for $52.32.
Let cuurent selling price : SP = $52.32
As they are making 9% profit now.
That means SP= Cp +0.09 CP , where Cp is the cost price of bag.
i..e ![52.32=Cp(1+0.09) \ \text{[Substituted value of SP in LHS and taking Cp common outside in RHS]}](https://tex.z-dn.net/?f=52.32%3DCp%281%2B0.09%29%20%5C%20%5Ctext%7B%5BSubstituted%20value%20of%20SP%20in%20LHS%20and%20taking%20Cp%20common%20outside%20in%20RHS%5D%7D)

i..e Cost price of bag = 48
Selling price to gain 20% profit = Cp+0.20CP
= CP(1+0.20)
=48 (1.20)
= 57.6
Hence, the selling price the businesswoman should ask in order to make 20% profit = $57.6
answer
240 standard versions
set up equations
s = number of standard versions
h = number of high quality versions
the total size of all standard versions would be 2.3s since each standard version is 2.3 MB
the total size of all high quality versions would be 4.4h since each standard version is 4.4 MB
add them together to get the total size (2664 MB) of all versions
2664 = 2.3s + 4.4h
since the high quality version was downloaded twice as often as the standard, we can say that
h = 2s
substitute h into equation and solve
2664 = 2.3s + 4.4h
h = 2s
2664 = 2.3s + 4.4(2s)
2664 = 2.3s + 8.8s
2664 = 11.1s
s = 2664/11.1
s = 240