From the system of equations, we have 3 unknowns and 3 equations. Therefore, it can be solved.
<span>3x - 2y + 2z = 30 (1)
</span><span>-x + 3y - 4z = -33 (2)
</span><span>2x - 4y + 3z = 42 (3)
We can write equation 2 x as a function of y and z and substitute the new equation to the other equations.
</span>x =3y - 4z + 33 (2)
3 (3y - 4z + 3)<span> - 2y + 2z = 30 (1)
</span>2 (3y - 4z + <span>3)</span> - 4y + 3z = 42 (3)
We simplify and solve the equations and we get values,
x = 4
y = -7
z = 2
Answer:
x = 5
x = 0
Pulling out like terms :
2.1 Pull out like factors :
x2 - 5x = x • (x - 5)
Equation at the end of step 2 :
x • (x - 5) = 0
Step 3 :
Theory - Roots of a product :
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation
1/3= 5/15
2/5= 6/15
5/15 + 6/15 = 11/15
15/15 - 11/15 = 4/15
Part C= 4/15
