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Feliz [49]
3 years ago
15

In the diagram, line a is the perpendicular bisector of KM. Line a is a perpendicular bisector of line segment K M. It intersect

s line segment K M at point L. Line a also contains point N. Line segment K L is 6 x + 4. Line segment K N is 9 x minus 5. Line segment N M is 7 x + 7. What is the length of KM? 22 units 40 units 44 units 80 units
Mathematics
2 answers:
AnnZ [28]3 years ago
8 0
The answer is 80


Step by step

Is


Below


Hopefully this help you

:)
qaws [65]3 years ago
7 0

Answer:

D. 80    :)

Step-by-step explanation:

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A car costs 25, 750.00 and depreciates in value by 20% per year. How much will the car be worth after 5 years
Virty [35]
I think its D. $20,600
3 0
3 years ago
Which of the following integrals represents the area of the region bounded by x = e and the functions f(x) = ln(x) and g(x) = lo
Neko [114]

Notice that

\log_{1/e}x=\dfrac{\ln x}{\ln\frac1e}=\dfrac{\ln x}{-\ln e}=-\ln x

f(x)=\ln x and g(x)=-\ln x intersect when x=1. For all x>1, we have \ln x>0 and -\ln x, so f(x)>g(x). Then the area we want is given by the integral,

\displaystyle\int_1^e\ln x-(-\ln x)\,\mathrm dx=2\int_1^e\ln x\,\mathrm dx

or in terms of \log_{1/e}x,

\displaystyle\int_1^e\ln x-\log_{1/e}x\,\mathrm dx

5 0
3 years ago
Find the slope, distance and midpoint between
Dovator [93]

Answer:

Slope- 4

Distance- 12.4

Midpoint- (6,8)

Step-by-step explanation:

Slope- \frac{y2-y1}{x2-x1}

\frac{2-14}{4-7} =\frac{-12}{-3}=4

Distance- d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

d = \sqrt{(4 - 7)^2 + (2-14)^2}

d = \sqrt{-3^2 + -12^2}d = \sqrt{144+9}=\sqrt{153}

\sqrt{153} = 12.4

Midpoint- \frac{x1+x2}{2} ,\frac{y1+y2}{2}

\frac{7+4}{2} =\frac{12}{2} = 6=x

\frac{14+2}{2} = \frac{16}{2} = 8 = y

(6,8)

6 0
3 years ago
Solve for x: 5x + 2 = 4x − 9.<br><br> 7<br> −7<br> 11<br> −11
irinina [24]
Simple....

you have:

5x+2=4x-9

5x+2=4x-9
-4x         -4x

x+2=-9

x+2=-9
   -2  -2

x=-11

Thus, your answer.
7 0
3 years ago
Read 2 more answers
Suppose that the functions s and t are defined for all real numbers x as follows.
Svetllana [295]
s(x)=2x+4;\ D_s=\mathbb{R}\\\\t(x)=5x;\ D_t=\mathbb{R}\\\\D_s=D_t\\\\(s+t)(x)=s(x)+t(x)=2x+4+5x=7x+4\\\\(s-t)(x)=s(x)-t(x)=2x+4-5x=-3x+4\\\\(s\times t)(x)=(2x+4)\times5x=10x^2+20x
8 0
3 years ago
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