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algol13
2 years ago
7

Can someone please help me asap!!

Mathematics
2 answers:
deff fn [24]2 years ago
4 0
The answer will be 24 23/100
Papessa [141]2 years ago
4 0
The answer for this question will 24 23/100. Hope it help!
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if you estimated your sale to be $300 but your actual sale was $345, what was your percent of the increase?
Nat2105 [25]

Answer:

The percentage change from 300 to 375 is 25 %

Step-by-step explanation:

((y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

((375 - 300) / 300) * 100 = 25 %

8 0
3 years ago
Please help ASAP I need this turned in! I don’t understand it!
ss7ja [257]

Car A: 3x + 6

Car B: 4x+8

Step-by-step explanation:

total: 7 (x+2)

7 0
2 years ago
In one paragraph explain step by step how to subtract 7 from 102
Anna11 [10]
To subtract 7 from 102, you have to regroup. You subtract 2 from 100, and 2 from 7, so it is 100-5. 100-5 is 95. The answer is 95. If you don't understand, tell me in the comments. This is just one method of subtracting.
8 0
3 years ago
Read 2 more answers
I need answer please​
zhenek [66]

Answer:

We know that lines <em>l</em><em> </em>and <em>m</em><em> </em>are parallel. The alternate interior angles rule states that the alternate interior angles formed by parallel lines are equal. So let's equate them.

2x + 22 = 4x

putting variables on one side,

22 = 4x - 2x

Thus 2x = 22

x becomes 22÷2

Therefore,<u> x = 11.</u>

pls give brainliest for the answer

8 0
2 years ago
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
2 years ago
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