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3 years ago

??? Anybody I need help finguring this out

Mathematics

2 answers:

Brilliant_brown [7]3 years ago

4 0

The correct answer is B

PSYCHO15rus [73]3 years ago

4 0

It’s B I think hmmmm

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Which restriction is appropriate for the variable 4a + 12 / a + 3

bonufazy [111]

I'll presume the slash is the fraction bar and the questioner is asking about

$\dfrac{4a+12}{a+3}$

That always equals 4 except when $a=-3$

So the restriction is

Answer: a ≠ -3

5 0

3 years ago

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A boy has in his pocket a 50-cent piece, two dimes and two pennies. If he pulls out a coin at random, what is the probability it

rodikova [14]

Well, from what I can tell he has 1 50 cent piece, 2 Dimes, and 2 Pennies. Meaning 5 objects in total, considering that it asks for "at least ten cents" that would mean the 2 Dimes and the 1 50 cent piece.
Since that is 3 objects out of the 5, being 3/5ths, that would mean he has a 60% chance or probability for the first draw.

Hopefully that helps. ^ ^
{-Ghostgate-}

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3 years ago

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The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$

$sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}$

$cos\angle AOB = \dfrac{Base}{Hypotenuse}$

$\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}$

$tan\angle AOB = \dfrac{Perpendicular}{Base}$

$\Rightarrow tan\angle AOB = \dfrac{3}{4}$

$cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}$

$\Rightarrow cosec\angle AOB = \dfrac{5}{3}$

$sec\angle AOB = \dfrac{Hypotenuse}{Base}$

$\Rightarrow sec\angle AOB = \dfrac{5}{4}$

$cot\angle AOB = \dfrac{Base}{Perpendicular}$

$\Rightarrow cot\angle AOB = \dfrac{4}{3}$

3 0

3 years ago

What are the coordinates of B if the midpoint of line segment AB is (2,-5) and the coordinates of point A is (4,4)?

Vlad1618 [11]

Answer:

i think it will be 20 unit diatance .

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3 years ago

As the value of the multiple coefficient of determination increases,

Leona [35]

Answer:

a.the goodness of fit for the estimated multiple regression equation increases.

Step-by-step explanation:

As the value of the multiple coefficient of determination increases,

a. the goodness of fit for the estimated multiple regression equation increases.

As we know that the coefficient of determination measures the variability of response variable with the help of regressor. As we know that if the value of the coefficient of determination increases strength of fit also increases.

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3 years ago