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3 years ago

G(x)=−2(x+1)(x+7) find the zeros

1 answer:

3 0

When finding zeros, the function has to equal zero. In other words, G(x) = 0.

For three multiplied parts to equal to zero, at least one has to be zero. -2 ≠ 0, but (x+1) or (x+7) can.

So you can equate each of those to zero and find out what the zeros are.

x+1=0
x=-1

x+7=0
x=-7

Thus the answer
x = -1 or -7

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Objects A and B are in harmonic motion modeled by

Zepler [3.9K]

Answer:

The phase difference between yA and yB is $\frac{-\pi }{12}$

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t - $\frac{\pi }{3}$ ) And

yB = 8 sin(2t - $\frac{\pi }{4}$ )

The function as written as :

y = a sin(ωt - Ф) where Ф is phase difference

So , phase difference between yA and yB = ( Ф_1 - Ф_2 )

Or phase difference between yA and yB = ( - $\frac{\pi }{3}$ + $\frac{\pi }{4}$ )

Or, phase difference between yA and yB = $(\frac{-4\pi +3\pi }{12})$

I.e phase difference between yA and yB = $\frac{-\pi }{12}$

Hence The phase difference between yA and yB is $\frac{-\pi }{12}$ Answer

4 0

3 years ago

Read 2 more answers

In his boat, Sheldon can travel 45 mi downstream in the same time that it takes to travel 9 mi upstream. If the rate of the curr

Nataliya [291]

Answer:

9 mph

Step-by-step explanation:

-let x be the speed of current and t be time. The speed equation for both directions can then be represented as:

$Speed=\frac{Distance}{Time}\\\\\#Upstream\\(u-6)t=9\\\\\#Donwstream\\\\(u+6)t=45$

#Since t is equal in both, we can do away with t.

#We the divide the downstream equation by the upstream equation as:

$\frac{u+6}{u-6}=\frac{45}{9}\\\\(u+6)=5(u-6)\\\\u+6=5u-30\\\\4u=36\\\\u=9$

Hence, the boat's speed in still water is 9 mph

7 0

3 years ago

Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and

Monica [59]

Step-by-step explanation:

We have got the lines :

$y=ax+b\\y=cx+d$

Both lines intercept the x-axis in the point :

$I = (i_{1} ,i_{2})$

In all point from x-axis the y-component is equal to 0.

$I=(i_{1},o)$

We replace the I point in the lines equations:

$0=a(i_{1})+b \\0=c(i_{1})+d$

From the first equation :

$0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}$

From the second equation :

$0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}$

Then $i_{1}=i_{1}$

Finally :

$\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc$

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0

3 years ago

Please tell me where I went Wrong. I am Confused

aivan3 [116]

The final answer would be 39/19 it doesn't simplify any more and if it did the 19 would be reduced as well as the 39

6 0

3 years ago

A survey showed that 77% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 22 adults are

Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

Step-by-step explanation:

A survey showed that 77% of adults need correction for their eyesight.

If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find $P(x\leq 11)$

$P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)$

Formula : $P(x=r)=^nC_r p^r q^{n-r}$

$P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}$

Using calculator

$P(x\leq 11)=0.00512$

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

3 0

3 years ago