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hodyreva [135]
2 years ago
10

Why wont it let me get another free trial on adobe photoshop?

Computers and Technology
1 answer:
k0ka [10]2 years ago
3 0
A free trial is a one-time thing. Try using another email address or something. 
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Group of answer choices When declaring a variable, you also specify the type of its values. Variables cannot be assigned and dec
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Complete Question:

Which of the following statement is true?

Group of answer choices.

A. When declaring a variable, you also specify the type of its values.

B. Variables cannot be assigned and declared in the same statement.

C. Variable names can be no more than 8 characters long.

D. Variable names must contain at least one dollar sign.

Answer:

A. When declaring a variable, you also specify the type of its values.

Explanation:

In Computer programming, a variable can be defined as a placeholder or container for holding a piece of information that can be modified or edited.

Basically, variable stores information which is passed from the location of the method call directly to the method that is called by the program.

For example, they can serve as a model for a function; when used as an input, such as for passing a value to a function and when used as an output, such as for retrieving a value from the same function. Therefore, when you create variables in a function, you can can set the values for their parameters.

For instance, to pass a class to a family of classes use the code;

\\parameter Name as Type (Keywords) = value;

\\procedure XorSwap (var a,b :integer) = "myvalue";

<em>Hence, the true and correct statement is that when declaring a variable, you also specify the type of its values such as integers, string, etc. </em>

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It creates an SQL statement to find the project that has the most employees from the same department. If more than one project m
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Answer:

Check the explanation

Explanation:

As per requirement submitted above kindly find below solution.

This demonstration is using SQL Server.

Table Names used as

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having count(emp_no)=(

select max(empCount) from (

select proj_name,dept_name,count(emp_no) empCount from project,department,works_on where project. proj_no=works_on. proj_no and department. dept_no=works_on. dept_no

group by proj_name,dept_name) as emp);

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3 years ago
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Types of computer viruses<br>​
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