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Fiesta28 [93]
3 years ago
10

4. which algebraic expression is a polynomial with a degree of 2? 4x3 − 2x 10x2 − 8x3 3 6x2 − 6x 5

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0
ANSWER

The algebraic expression that is a polynomial with a degree of 2 is
6 {x}^{2}  - 6x + 5



EXPLANATION

The degree of a term of a polynomial is the total sum of the exponents of the variables in each term.


The highest degree of the polynomial is considered the degree of the polynomial.



For first option,
4 {x}^{3}  - 2x + 10
the highest degree is 3.



The second option is,
{x}^{2}  - 8 {x}^{3}  + 3
This polynomial also has a degree of 3.



The third option is,
6 {x}^{2}  - 6x + 5
This last option has a degree of 2.


Therefore the correct answer is option C.
Amiraneli [1.4K]3 years ago
3 0

Answer:

6x²-6x+5

Step-by-step explanation:

The degree of a polynomial is the highest power of x existing in a polynomial.

Now we will check every option

4x³-2x : The degree of this polynomial is three

10x²-8x³+3: The degree of this polynomial is also 3

6x²-6x+5: The degree of this polynomial is 2

Hence, the correct answer is:

6x²-6x+5

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3 years ago
Can anyone help me ? I just need the numbers
Nimfa-mama [501]

Answer:

<em>(-6, 0) and  (0, 1.5)</em>

<em></em>

Step-by-step explanation:

The equation of the line in pint slope form is expressed as;

y-y0= m(x-x0)

m is the slope

(x0, y0) is the point on the line

Given

m = 1/4

(x0, y0) = (6,3)

Substitute into the formula;

y - 3 =  1/4(x-6)

4(y-3) = x - 6

4y - 12 = x-6

4y - x = -6+12

4y - x = 6

x = 4y - 6

To get the points to plot, we will find the x and y-intercept of the resulting expression.

For the x-intercept,

at y = 0

x = 4(0) - 6

x = -6

Hence the x-intercept is at (-6, 0)

For the y-intercept,

at x = 0

0 = 4y - 6

4y = 6

y = 6/4

y = 3/2

y = 1.5

Hence the y-intercept is at (0, 1.5)

<em>Hence the required points to plot to get the required line are  (-6, 0) and  (0, 1.5)</em>

<em></em>

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3 years ago
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avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
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To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4  or 1.85
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Therefore, the zeros of the quadratic equation are 1.85 and -1.35. 
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