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r-ruslan [8.4K]
3 years ago
14

Probability help!!!!!

Mathematics
1 answer:
nirvana33 [79]3 years ago
7 0

Let A be the event A=\{choosing \;an \;odd \;number\} and B be the vent B=\{choosing \;an \;even \;number\}. Since the intersection of the events A\cap B=\phi, the events A and B are mutually exclusive.

The number is either odd or even. Since P(A)+P(B)=1, the events are mutually exclusive and exhaustive.

Correct choice is "the number is either odd or even".

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Zarrin [17]
Awnser:69
I had this question a few minutes ago, that’s funny
7 0
3 years ago
Can someone help me asap!<br><br> ​
lilavasa [31]

Answer:

B negative

Step-by-step explanation:

use real numbers?

n is +9

m is -11

m/n * (-m*n^2)

-11/9 * (11*81)

-11/1 * (11*9)

-11 * 99

-1089

6 0
2 years ago
Pls help! will mark brainliest if correct
nevsk [136]

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3 0
3 years ago
Angle B and angle C are complementary. If angle B is five times the size of angle C what is the measurements of both angles.
faltersainse [42]

Step-by-step explanation:

Let Angle C be x

So angle B will be 5x

Since they both are complementary, we can come up with this equation.

x+5x=90 degrees

6x=90 degrees

x=90/6,x=15

Measures of Angles

Angle C=x=15 degrees

Angle B=5x=5*15=75 degrees

PLEASE FOLLOW ME AND MARK AS BRAINILIEST

3 0
3 years ago
What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in
xeze [42]

ANSWER

197 {in}^{2}

EXPLANATION

The area of the two tra-pezoidal faces

= 2 \times  \frac{1}{2}  \times (9 + 5) \times 5 = 70 {in}^{2}

The area of the 5 by 6.4 rectangular face

= 6.4 \times 5 = 32  {in}^{2}

The area of the two square faces

= 2(5 \times 5) = 50 {in}^{2}

The area of the 9 by 5 rectangular face is

= 9 \times 5 = 45 {in}^{2}

The surface area of the design is:

70 + 32 + 50  + 45=197 {in}^{2}

6 0
3 years ago
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