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krek1111 [17]
4 years ago
6

A motorcycle at a stoplight takes 5.22 seconds to accelerate to a speed of 33.0 m/s after the light turns green. What is the ave

rage acceleration of the motorcycle?
Physics
2 answers:
zimovet [89]4 years ago
8 0
(33 m/s ) / 5.22 s = 6.32m/ s^2
Sedbober [7]4 years ago
4 0

Answer:

6.33 m/s²

Explanation:

Acceleration is defined as the division of the change in speed by the time elapsed for that speed change. In this case, the motorcycle goes from 0 m/s (it was stopped) to 33 m/s in 5.22 seconds, then its acceleration is:

a = 33/5.22 = 6.33 m/s²

The dimensions must be divided too. In this case we have to divide m/s by s, and we get m/(s*s) or m/s²

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Sloan [31]

Answer:

A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.

Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.

4 0
3 years ago
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Before using a string in a comparison, you can use either the To Upper method or the To Lower method to convert the string to up
diamong [38]

Answer:

True, check attachment for code

Explanation:

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The fourth line is where the conversion is done.

We can compare the string

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Check attachment for the code

3 0
4 years ago
The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 419
oee [108]

Answer:

d. 149 ⁰C.

Explanation:

Given;

mass of the block of ice, m = 2 kg

specific heat capacity of the ice, C = 2090 J/(kgK)

initial temperature of the ice, t₁ = -90 ⁰C

heat added to the ice, H = 1,000,000 J

let the final temperature of the ice = t₂

The final temperature of the ice after adding the heat is calculated as follows;

H = mC_{ice} \Delta t\\\\H = mC_{ice}  (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C

Therefore, the new temperature of the water is 149 ⁰C.

4 0
3 years ago
Plz help it’s passed due!
pickupchik [31]
It is b 9.1 :) have a nice day
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4 years ago
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